Equations balanced on the previous day | Equations balanced on the next day |
2 HClO3 + CaCO3 = CaCl2 + H2O + CO2 + 3 O2
CH4 + CO2 = C12O12 + H2 =>
6 CH4 + 6 CO2 = C12O12 + 12 H2
C + N = C2N2 =>
2 C + 2 N = C2N2
[Cu(NH3)4(OH2)2]SO4 + NaOH = Cu(OH)2 + Na2SO4 + NH3 + H2O =>
[Cu(NH3)4(OH2)2]SO4 + 2 NaOH = Cu(OH)2 + Na2SO4 + 4 NH3 + 2 H2O
C + N = C3N4 =>
3 C + 4 N = C3N4
MgBr2 + Fe2{+} = Mg2{+} + FeBr2 =>
2 MgBr2 + Fe2{+} = Mg2{+} + 2 FeBr2
K2Cr2O7 + NaI + H2O = Cr(OH)3 + KOH + NaOH + I2 =>
K2Cr2O7 + 6 NaI + 7 H2O = 2 Cr(OH)3 + 2 KOH + 6 NaOH + 3 I2
HCl + C14H14N3NaO3S = H(N3)Na(O3)S + C14H14Cl =>
HCl + C14H14N3NaO3S = H(N3)Na(O3)S + C14H14Cl
Fe3O4 + CO = FeO + CO2 =>
Fe3O4 + CO = 3 FeO + CO2
HF + NaOH = NaF + H2O =>
HF + NaOH = NaF + H2O
Pb(NO3)2 + Na3I = Pb3I2 + Na(NO3) =>
3 Pb(NO3)2 + 2 Na3I = Pb3I2 + 6 Na(NO3)
PH3 + O2 = P5O10 + H2O =>
20 PH3 + 35 O2 = 4 P5O10 + 30 H2O
PH3 + O2 = P5O10 + H2O =>
20 PH3 + 35 O2 = 4 P5O10 + 30 H2O
Cu2S + HNO3 = Cu(NO3)2 + CuSO4 + NO + H2O =>
3 Cu2S + 16 HNO3 = 3 Cu(NO3)2 + 3 CuSO4 + 10 NO + 8 H2O
Cu(I) + oxygen = Cu(I)O =>
2 Cu(I) + O2 = 2 Cu(I)O
SO2 + KCr2 = K2O + Cr2 + S =>
SO2 + 4 KCr2 = 2 K2O + 4 Cr2 + S
NaCl + KMnO4 + H2SO4 = NaHSO4 + Cl2 + KHSO4 + MnSO4 + H2O =>
10 NaCl + 2 KMnO4 + 14 H2SO4 = 10 NaHSO4 + 5 Cl2 + 2 KHSO4 + 2 MnSO4 + 8 H2O
HNO3 + H3PO4 = HNO3(PO4)3 + H =>
HNO3 + 3 H3PO4 = HNO3(PO4)3 + 9 H
K2CO3 + CaCO3 = K2Ca(CO3)2 =>
K2CO3 + CaCO3 = K2Ca(CO3)2
C + N = CN2 =>
C + 2 N = CN2
HNO3 + Al(OH)3 = Al(NO3)3 + H2O =>
3 HNO3 + Al(OH)3 = Al(NO3)3 + 3 H2O
FeCl3 + NaOH = Fe(OH)3 + NaCl =>
FeCl3 + 3 NaOH = Fe(OH)3 + 3 NaCl
KClO3 = KCl + O2 =>
2 KClO3 = 2 KCl + 3 O2
FeS + O2 = Fe2O3 + SO2 =>
4 FeS + 7 O2 = 2 Fe2O3 + 4 SO2
KMnO4 + Fe2C2O4 = CO2 + Fe2O3 + KMnO2 =>
3 KMnO4 + 2 Fe2C2O4 = 4 CO2 + 2 Fe2O3 + 3 KMnO2
C20H14O4 + H2O = H2C20H14O4 + OH =>
C20H14O4 + 2 H2O = H2C20H14O4 + 2 OH
X4Y10 + O2 = XO2 + Y20 =>
2 X4Y10 + 8 O2 = 8 XO2 + Y20
[Cu(NH3)4]SO4*H2O + HCl = CuSO4 + H2O + NH4Cl =>
[Cu(NH3)4]SO4*H2O + 4 HCl = CuSO4 + H2O + 4 NH4Cl
PH3 + O2 = P5O10 + H2O =>
20 PH3 + 35 O2 = 4 P5O10 + 30 H2O
CH3COOC2H5 + H2O = CH3COOH + C2H5 =>
5 CH3COOC2H5 + 2 H2O = 6 CH3COOH + 4 C2H5
Ba(NO3)2 + CO3 = Ba + CO3(NO3)2 =>
Ba(NO3)2 + CO3 = Ba + CO3(NO3)2
Fe(NH4)2(SO4)2*6H2O + H2C2O4*2H2O + K2C2O4*H2O + H2O2 = K3Fe(C2O4)3*3H2O + (NH4)2SO4 + H2SO4 + H2O =>
2 Fe(NH4)2(SO4)2*6H2O + 3 H2C2O4*2H2O + 3 K2C2O4*H2O + H2O2 = 2 K3Fe(C2O4)3*3H2O + 2(NH4)2SO4 + 2 H2SO4 + 17 H2O
CuSO4(aq) + Al(s) = AlSO4(s) + Cu(aq) =>
CuSO4(aq) + Al(s) = AlSO4(s) + Cu(aq)
KCl + H2SO4 = SO2 + K2O + Cl2 + H2O =>
2 KCl + H2SO4 = SO2 + K2O + Cl2 + H2O
Na2MoO4 + K2MoO4 + MoO3 + Mo = Na6K3Mo60O170 =>
18 Na2MoO4 + 9 K2MoO4 + 304 MoO3 + 29 Mo = 6 Na6K3Mo60O170
HClO2 + H2O = OH{-} + H2ClO2{+} =>
HClO2 + H2O = OH{-} + H2ClO2{+}
TiCl3 + H2O = Ti(OH)3 + HCl =>
TiCl3 + 3 H2O = Ti(OH)3 + 3 HCl
KAI(OH)4 + H2SO4 = AI(OH)3 + K2SO4 + H2O =>
2 KAI(OH)4 + H2SO4 = 2 AI(OH)3 + K2SO4 + 2 H2O
H2SO4 + Fe(OH)2 = Fe2(SO4)3 + S2 + H2O =>
20 H2SO4 + 12 Fe(OH)2 = 6 Fe2(SO4)3 + S2 + 32 H2O
Ba(NO3)2 + CO3 = Ba + CO3(NO3)2 =>
Ba(NO3)2 + CO3 = Ba + CO3(NO3)2
(NH4)2(SO4) + AgNO3 = NH4NO3 + Ag2SO4 =>
(NH4)2(SO4) + 2 AgNO3 = 2 NH4NO3 + Ag2SO4
NiCl2 + Al = AlCl3 + Ni =>
3 NiCl2 + 2 Al = 2 AlCl3 + 3 Ni
KMnO4 + KBr + HCl = MnCl2 + KCl + Br2 + H2O =>
2 KMnO4 + 10 KBr + 16 HCl = 2 MnCl2 + 12 KCl + 5 Br2 + 8 H2O
CH3(CH2)2CH3 + O2 = CO2 + H2O =>
2 CH3(CH2)2CH3 + 13 O2 = 8 CO2 + 10 H2O
PH3 + O2 = P5O10 + H2O =>
20 PH3 + 35 O2 = 4 P5O10 + 30 H2O
Ce3CO2 = Ce + CO2 =>
Ce3CO2 = 3 Ce + CO2
NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O
KClO3 + Fe(NO3)2 + HNO3 = Fe(NO3)3 + KCl + H2O =>
KClO3 + 6 Fe(NO3)2 + 6 HNO3 = 6 Fe(NO3)3 + KCl + 3 H2O
K2Cr2O7 + HCl = HClO3 + KCl + CrCl3 + H2O =>
K2Cr2O7 + 9 HCl = HClO3 + 2 KCl + 2 CrCl3 + 4 H2O
CrO3 + C6H10O5 = Cr + H2O + CO =>
2 CrO3 + C6H10O5 = 2 Cr + 5 H2O + 6 CO
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 03/22/24
Equations balanced on 04/21/23
-donnez-nous vos commentaires de votre expérience avec l'équilibreur d'équation chimique.