Printed from https://www.webqc.org

Chemical Equations Balanced on 07/03/10

 Equations balanced on the previous day Equations balanced on the next day
Balance equation of any chemical reaction online for free
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
HBF4 + NaOH = H3BO3 + NaF + H2O =>
HBF4 + 4 NaOH = H3BO3 + 4 NaF + H2O

H2SiF6 + NaOH = Na2SiF6 + H2O =>
H2SiF6 + 2 NaOH = Na2SiF6 + 2 H2O

HBF4 + NaOH = H3BO3 + NaF + H2O =>
HBF4 + 4 NaOH = H3BO3 + 4 NaF + H2O

MnO2 + CO = Mn2O3 + CO2 =>
2 MnO2 + CO = Mn2O3 + CO2

Ca(OH)2 + H3PO4 = H2O + Ca3(PO4)2 =>
3 Ca(OH)2 + 2 H3PO4 = 6 H2O + Ca3(PO4)2

Ca(OH)2 + H3PO4 = H2O + Ca3(PO4)2 =>
3 Ca(OH)2 + 2 H3PO4 = 6 H2O + Ca3(PO4)2

NH3 + O2 = NO2 + H2O =>
4 NH3 + 7 O2 = 4 NO2 + 6 H2O

MgF2 = Mg + F =>
MgF2 = Mg + 2 F

OH + HCN = CNO + H2O =>
3 OH + HCN = CNO + 2 H2O

FeCl3(aq) + NaOH(aq) = Fe(OH)3(s) + NaCl(aq) =>
FeCl3(aq) + 3 NaOH(aq) = Fe(OH)3(s) + 3 NaCl(aq)

FeCl3(aq) + NaOH(aq) = Fe(OH)3(s) + NaCl(aq) =>
FeCl3(aq) + 3 NaOH(aq) = Fe(OH)3(s) + 3 NaCl(aq)

H2O + CrO4 = Cr(OH)4 + OH =>
4 H2O + CrO4 = Cr(OH)4 + 4 OH

FeCl3(aq) + NaOH(aq) = Fe(OH)3(s) + NaCl(aq) =>
FeCl3(aq) + 3 NaOH(aq) = Fe(OH)3(s) + 3 NaCl(aq)

HNO3 + Ba(OH)2 = H2O + Ba(NO3)2 =>
2 HNO3 + Ba(OH)2 = 2 H2O + Ba(NO3)2

FeS + O2 = Fe2O3 + SO2 =>
4 FeS + 7 O2 = 2 Fe2O3 + 4 SO2

C2H4 + O2 = CO2 + H2O =>
C2H4 + 3 O2 = 2 CO2 + 2 H2O

KClO3 = KCl + O2 =>
2 KClO3 = 2 KCl + 3 O2

N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3

NaHCO3 = Na2CO3 + CO2 + H2O =>
2 NaHCO3 = Na2CO3 + CO2 + H2O

FeCl3(aq) + NaOH(aq) = Fe(OH)3(s) + NaCl(aq) =>
FeCl3(aq) + 3 NaOH(aq) = Fe(OH)3(s) + 3 NaCl(aq)

AgNO3 + KCl = AgCl + KNO3 =>
AgNO3 + KCl = AgCl + KNO3

H2 + C2H4 = C2H6 =>
H2 + C2H4 = C2H6

CO2 + H2O = H2CO3 =>
CO2 + H2O = H2CO3

H2 + F2 = HF =>
H2 + F2 = 2 HF

H2 + C2H4 = C2H6 =>
H2 + C2H4 = C2H6

H3PO4 + Na(OH) = Na3PO4 + H2O =>
H3PO4 + 3 Na(OH) = Na3PO4 + 3 H2O

O2 + H2 = H2O =>
O2 + 2 H2 = 2 H2O

Fe{3+} + I{-} = Fe{2+} + I2 =>
2 Fe{3+} + 2 I{-} = 2 Fe{2+} + I2

H2SO4 + Ca(OH)2 = CaSO4 + H2O =>
H2SO4 + Ca(OH)2 = CaSO4 + 2 H2O

N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3

Na(s) + Cu(NO3)2 = NaNO3 + Cu(s) =>
2 Na(s) + Cu(NO3)2 = 2 NaNO3 + Cu(s)

C12H24 + O2 = CO + H2O =>
C12H24 + 12 O2 = 12 CO + 12 H2O

Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

Fe2O3 + H2 = Fe + H2O =>
Fe2O3 + 3 H2 = 2 Fe + 3 H2O

HCl(aq) + HNO3(aq) + Sn(s) = NO2(g) + H2SnCl6(aq) + H2O(l) =>
6 HCl(aq) + 4 HNO3(aq) + Sn(s) = 4 NO2(g) + H2SnCl6(aq) + 4 H2O(l)

C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O

K2Cr2O7(aq) + HI(aq) = KI(aq) + CrI3(aq) + I2(s) + H2O(l) =>
K2Cr2O7(aq) + 14 HI(aq) = 2 KI(aq) + 2 CrI3(aq) + 3 I2(s) + 7 H2O(l)

FeC2O4 = Fe + CO2 =>
FeC2O4 = Fe + 2 CO2

FeC2O4 = FeO + CO + CO2 =>
FeC2O4 = FeO + CO + CO2

Mg3N2 + H2O = Mg(OH)2 + NH3 =>
Mg3N2 + 6 H2O = 3 Mg(OH)2 + 2 NH3

S2O8{2-} + I{-} = SO4{2-} + I3{-} =>
S2O8{2-} + 3 I{-} = 2 SO4{2-} + I3{-}

Na3PO4 + Ba(NO3)2 = NaNO3 + Ba3(PO4)2 =>
2 Na3PO4 + 3 Ba(NO3)2 = 6 NaNO3 + Ba3(PO4)2

CaSO4 + AlCl3 = CaCl2 + Al2(SO4)3 =>
3 CaSO4 + 2 AlCl3 = 3 CaCl2 + Al2(SO4)3

H3PO4 + Mg(OH)2 = Mg3(PO4)2 + H2O =>
2 H3PO4 + 3 Mg(OH)2 = Mg3(PO4)2 + 6 H2O

HNO3(aq) + KI(aq) = NO(g) + I2(s) + H2O(l) + KNO3(aq) =>
8 HNO3(aq) + 6 KI(aq) = 2 NO(g) + 3 I2(s) + 4 H2O(l) + 6 KNO3(aq)

HNO3(aq) + KI(aq) = NO(g) + I2(s) + H2O(l) + KNO3(aq) =>
8 HNO3(aq) + 6 KI(aq) = 2 NO(g) + 3 I2(s) + 4 H2O(l) + 6 KNO3(aq)

K2S + BaCl2 = KCl + BaS =>
K2S + BaCl2 = 2 KCl + BaS

K2S(aq) + BaCl2(aq) = KCl + BaS =>
K2S(aq) + BaCl2(aq) = 2 KCl + BaS

K2S + BaCl2 = KCl + BaS =>
K2S + BaCl2 = 2 KCl + BaS

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Balance equation of any chemical reaction online for free
 Equations balanced on the previous day Equations balanced on the next day
Equations balanced on 06/26/10
Equations balanced on 06/03/10
Equations balanced on 07/03/09
-donnez-nous vos commentaires de votre expérience avec l'équilibreur d'équation chimique.
Menu Équilibrer Masse molaire Lois des gaz Unités Outils pour la chimie Tableau périodique Forum de la chimie Symétrie Constantes Contribuer Contactez-nous
Comment citer ?