Chemical Equations Balanced on 12/23/15

OH{-} + CrI₃ + Cl₂ = CrO₄{2-} + I₂ + Cl{-} + H₂₀ =>
40 OH{-} + 10 CrI₃ + 10 Cl₂ = 10 CrO₄{2-} + 15 I₂ + 20 Cl{-} + 2 H₂₀

OH{-} + CrI₃ + Cl₂ = CrO₄{2-} + I₂ + Cl{-} + H₂₀ =>
40 OH{-} + 10 CrI₃ + 10 Cl₂ = 10 CrO₄{2-} + 15 I₂ + 20 Cl{-} + 2 H₂₀

OH{-} + CrI₃ + Cl₂ = CrO₄{2-} + I₂ + Cl{-} + H₂₀ =>
40 OH{-} + 10 CrI₃ + 10 Cl₂ = 10 CrO₄{2-} + 15 I₂ + 20 Cl{-} + 2 H₂₀

Al(NO₃)₃ + H₃BO₃ + CH₄N₂O = AlBO₃ + CO₂ + H₂O + N₂ =>
2 Al(NO₃)₃ + 2 H₃BO₃ + 5 CH₄N₂O = 2 AlBO₃ + 5 CO₂ + 13 H₂O + 8 N₂

SbH₃ + HNO₃ = Sb₂O₅ + NO + H₂₀ =>
80 SbH₃ + 100 HNO₃ = 40 Sb₂O₅ + 100 NO + 17 H₂₀

NH₃ + O₂ = NO + H₂O =>
4 NH₃ + 5 O₂ = 4 NO + 6 H₂O

SbH₃ + HNO₃ = Sb₂O₅ + NO + H₂O =>
6 SbH₃ + 16 HNO₃ = 3 Sb₂O₅ + 16 NO + 17 H₂O

Cr₂S₃ + KOH + KClO₃ = K₂CrO₄ + K₂SO₄ + KCl + H₂O =>
Cr₂S₃ + 10 KOH + 5 KClO₃ = 2 K₂CrO₄ + 3 K₂SO₄ + 5 KCl + 5 H₂O

KOH + H₂CO₃ = K₂CO₃ + H₂O =>
2 KOH + H₂CO₃ = K₂CO₃ + 2 H₂O

Cr(NO₃)₃ + H₂O₂ + KOH = K₂CrO₄ + KNO₃ + H₂O =>
2 Cr(NO₃)₃ + 3 H₂O₂ + 10 KOH = 2 K₂CrO₄ + 6 KNO₃ + 8 H₂O