Equations balanced on the previous day | Equations balanced on the next day |
9 Ba(NO3)2 + 5 C6H8O7 = 9 BaO + 20 H2O + 30 CO2 + 9 N2
K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O
Na3PO4 + CaCl2 = Ca3(PO4)2 + NaCl =>
2 Na3PO4 + 3 CaCl2 = Ca3(PO4)2 + 6 NaCl
C2H2 + O2 = CO2 + H2O =>
2 C2H2 + 5 O2 = 4 CO2 + 2 H2O
Na3PO4 + CaCrO4 = Na2CrO4 + Ca3(PO4)2 =>
2 Na3PO4 + 3 CaCrO4 = 3 Na2CrO4 + Ca3(PO4)2
AlBr3 + K2SO4 = KBr + Al2(SO4)3 =>
2 AlBr3 + 3 K2SO4 = 6 KBr + Al2(SO4)3
H3PO4 + NaBr = HBr + Na3PO4 =>
H3PO4 + 3 NaBr = 3 HBr + Na3PO4
Th(NO3)4 + K3(PO4) = Th3(PO4)4 + K(NO3) =>
3 Th(NO3)4 + 4 K3(PO4) = Th3(PO4)4 + 12 K(NO3)
NaNO3 + KC2H3O2 = NaC2H3O2 + KNO3 =>
NaNO3 + KC2H3O2 = NaC2H3O2 + KNO3
Ba(NO3)2 + C6H8O7 = BaO + H2O + CO2 + N2 =>
9 Ba(NO3)2 + 5 C6H8O7 = 9 BaO + 20 H2O + 30 CO2 + 9 N2
Fe2O3 + CO = Fe + CO2 =>
Fe2O3 + 3 CO = 2 Fe + 3 CO2
Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2
Pb(C2H3O2)2 + K2CrO4 = PbCrO4 + KC2H3O2 =>
Pb(C2H3O2)2 + K2CrO4 = PbCrO4 + 2 KC2H3O2
Na2CO3 + HCl = NaCl + H2O + CO2 =>
Na2CO3 + 2 HCl = 2 NaCl + H2O + CO2
ZrO(NO3)2 + C6H8O7 = ZrO2 + H2O + CO2 + N2 =>
9 ZrO(NO3)2 + 5 C6H8O7 = 9 ZrO2 + 20 H2O + 30 CO2 + 9 N2
Pb(NO3)2 + K2CrO4 = PbCrO4 + KNO3 =>
Pb(NO3)2 + K2CrO4 = PbCrO4 + 2 KNO3
C4H10 + O2 = CO2 + H2O =>
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
HCl(aq) + K2CrO7(aq) + C2H5OH(aq) = CrCl3(aq) + CO2(g) + KCl(aq) + H2O(l) =>
20 HCl(aq) + 4 K2CrO7(aq) + 3 C2H5OH(aq) = 4 CrCl3(aq) + 6 CO2(g) + 8 KCl(aq) + 19 H2O(l)
AgC2H3O2 + AlBr3 = Al(C2H3O2)3 + AgBr =>
3 AgC2H3O2 + AlBr3 = Al(C2H3O2)3 + 3 AgBr
CuO + H2 = Cu + H2O =>
CuO + H2 = Cu + H2O
Sr + Cl2 + O2 = Sr(ClO3)2 =>
Sr + Cl2 + 3 O2 = Sr(ClO3)2
HgO = Hg + O2 =>
2 HgO = 2 Hg + O2
IO3{-} + I{-} + H{+} = I2 + H2O =>
IO3{-} + 5 I{-} + 6 H{+} = 3 I2 + 3 H2O
HCl + CaCO3 = CaCl2 + H2O + CO2 =>
2 HCl + CaCO3 = CaCl2 + H2O + CO2
H2 + N2 = NH3 =>
3 H2 + N2 = 2 NH3
Zn + Pb(NO3)2 = Zn(NO3)2 + Pb =>
Zn + Pb(NO3)2 = Zn(NO3)2 + Pb
HCl + CaCO3 = CaCl2 + H2O + CO2 =>
2 HCl + CaCO3 = CaCl2 + H2O + CO2
LIOH = LI + OH =>
LIOH = LI + OH
NH4NO3 = N2O + H2O =>
NH4NO3 = N2O + 2 H2O
H2OZrO(NO3)2 + C6H8O7 = ZrO2 + H2O + CO2 + N2 =>
9 H2OZrO(NO3)2 + 5 C6H8O7 = 9 ZrO2 + 29 H2O + 30 CO2 + 9 N2
NH4CL + NANO2 = N2 + H2O + NACL =>
NH4CL + NANO2 = N2 + 2 H2O + NACL
NH3 + Cl2 = N2H4 + NH4Cl =>
4 NH3 + Cl2 = N2H4 + 2 NH4Cl
Mg(CN)2 + KNO3 = Mg(NO3)2 + KCN =>
Mg(CN)2 + 2 KNO3 = Mg(NO3)2 + 2 KCN
K2CO3 + CH3CO2H = KCH3CO2 + CO2 + H2O =>
K2CO3 + 2 CH3CO2H = 2 KCH3CO2 + CO2 + H2O
H2C2O4 + KMnO4 = CO2 + K2CO3 + MnO2 + H2O =>
3 H2C2O4 + 2 KMnO4 = 5 CO2 + K2CO3 + 2 MnO2 + 3 H2O
C5H10O2 + O2 = CO2 + H2O =>
2 C5H10O2 + 13 O2 = 10 CO2 + 10 H2O
HCl + NaOH = NaCl + H2O =>
HCl + NaOH = NaCl + H2O
NaBr + H3PO4 = Na3PO4 + HBr =>
3 NaBr + H3PO4 = Na3PO4 + 3 HBr
ZnCO3 + H(NO3) = Zn(NO3)2 + CO2 + H2O =>
ZnCO3 + 2 H(NO3) = Zn(NO3)2 + CO2 + H2O
AgNO3(aq) + Cu(s) = Cu(NO3)2(aq) + Ag(s) =>
2 AgNO3(aq) + Cu(s) = Cu(NO3)2(aq) + 2 Ag(s)
KrF2 + H2O = Kr + O2 + HF =>
2 KrF2 + 2 H2O = 2 Kr + O2 + 4 HF
CH4 + O2 = CO2 + H2O =>
CH4 + 2 O2 = CO2 + 2 H2O
FeCl3 + Na3PO4 = FePO4 + NaCl =>
FeCl3 + Na3PO4 = FePO4 + 3 NaCl
Al2O3 + Fe = Fe3O4 + Al =>
4 Al2O3 + 9 Fe = 3 Fe3O4 + 8 Al
Hg(NO3)2 + K3PO4 = Hg3(PO4)2 + KNO3 =>
3 Hg(NO3)2 + 2 K3PO4 = Hg3(PO4)2 + 6 KNO3
C3H7OH + O2 = CO2 + H2O =>
2 C3H7OH + 9 O2 = 6 CO2 + 8 H2O
As2S5(s) + NaNO3(aq) + HCl(aq) = H3AsO4(aq) + NaHSO4(aq) + NO2(g) + H2O(l) + NaCl(aq) =>
As2S5(s) + 40 NaNO3(aq) + 35 HCl(aq) = 2 H3AsO4(aq) + 5 NaHSO4(aq) + 40 NO2(g) + 12 H2O(l) + 35 NaCl(aq)
NO3{-} + Cu + H3O{+} = NO + Cu2{+} + H2O =>
NO3{-} + 6 Cu + 4 H3O{+} = NO + 3 Cu2{+} + 6 H2O
H2SO4 + B(OH)3 = B2(SO4)3 + H2O =>
3 H2SO4 + 2 B(OH)3 = B2(SO4)3 + 6 H2O
NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/30/16
Equations balanced on 01/29/16
-donnez-nous vos commentaires de votre expérience avec l'équilibreur d'équation chimique.