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Balance equation of any chemical reaction online for free
NaCl + F2 = NaF + Cl2 => 2 NaCl + F2 = 2 NaF + Cl2
SnO2 + H2 = Sn + H2O => SnO2 + 2 H2 = Sn + 2 H2O
FeO + C = Fe + CO => FeO + C = Fe + CO
NaCl = Na + Cl2 => 2 NaCl = 2 Na + Cl2
Fe2(SO4)3 + NaBr = Br2 + FeSO4 + Na2SO4 => Fe2(SO4)3 + 2 NaBr = Br2 + 2 FeSO4 + Na2SO4
Na2CO3 + C + N2 = NaCN + CO => Na2CO3 + 4 C + N2 = 2 NaCN + 3 CO
KClO3 = KCl + O2 => 2 KClO3 = 2 KCl + 3 O2
K3PO4 + HCI = KCI + H3PO4 => K3PO4 + 3 HCI = 3 KCI + H3PO4
NaBr + F2 = NaF + Br2 => 2 NaBr + F2 = 2 NaF + Br2
C4H10 + O2 = CO2 + H20 => 2 C4H10 + 8 O2 = 8 CO2 + H20
C6H12O6 = C2H5OH + CO2 => C6H12O6 = 2 C2H5OH + 2 CO2
KOH + H3PO4 = K3PO4 + H2O => 3 KOH + H3PO4 = K3PO4 + 3 H2O
KNO3 = KNO2 + O2 => 2 KNO3 = 2 KNO2 + O2
CHO + O2 = CO2 + H2O => 4 CHO + 3 O2 = 4 CO2 + 2 H2O
Fe(OH)2 + H3PO4 = Fe3(PO4)2 + H2O => 3 Fe(OH)2 + 2 H3PO4 = Fe3(PO4)2 + 6 H2O
K2CrO4 + K2S + H2O = Cr(OH)3 + K2SO4 + KOH => 8 K2CrO4 + 3 K2S + 20 H2O = 8 Cr(OH)3 + 3 K2SO4 + 16 KOH
CuCl2 + Na2S = CuS + NaCl => CuCl2 + Na2S = CuS + 2 NaCl
KI + Pb(NO3)2 = KNO3 + PbI2 => 2 KI + Pb(NO3)2 = 2 KNO3 + PbI2
Na + O2 = Na2O => 4 Na + O2 = 2 Na2O
KBR + Cl2 = KCl + BR => 2 KBR + Cl2 = 2 KCl + 2 BR
NaNO3 = NaNO2 + O2 => 2 NaNO3 = 2 NaNO2 + O2
FeCl3 + Nh4Oh = Fe(Oh)3 + Nh4Cl => FeCl3 + 3 Nh4Oh = Fe(Oh)3 + 3 Nh4Cl
SeCl6 + O2 = SeO2 + Cl2 => SeCl6 + O2 = SeO2 + 3 Cl2
AgNO3 + Cu = Cu(NO3)2 + Ag => 2 AgNO3 + Cu = Cu(NO3)2 + 2 Ag
Fe2(SO4)3 + Ca(OH)2 = Fe(OH)3 + Ca(SO4) => Fe2(SO4)3 + 3 Ca(OH)2 = 2 Fe(OH)3 + 3 Ca(SO4)
C7H17 + O2 = CO2 + H20 => 20 C7H17 + 140 O2 = 140 CO2 + 17 H20
Cu + HNO3 = Cu(NO3)2 + NO + H2O => 3 Cu + 8 HNO3 = 3 Cu(NO3)2 + 2 NO + 4 H2O
CaC2 + H2O = C2H2 + Ca(OH)2 => CaC2 + 2 H2O = C2H2 + Ca(OH)2
HClO3 + NaOH = NaClO3 + H2O => HClO3 + NaOH = NaClO3 + H2O
KCl + Br2 = KBr + Cl2 => 2 KCl + Br2 = 2 KBr + Cl2
KBR + Cl2 = KCl + BR => 2 KBR + Cl2 = 2 KCl + 2 BR
C11H17N5O2 + O2 = CO2 + H2O + N2 => 4 C11H17N5O2 + 57 O2 = 44 CO2 + 34 H2O + 10 N2
NaOH + H3PO4 = Na3PO4 + H2O => 3 NaOH + H3PO4 = Na3PO4 + 3 H2O
NaOH + H3PO4 = Na3PO4 + H2O => 3 NaOH + H3PO4 = Na3PO4 + 3 H2O
H3PO4 + NH3 = ((NH4)3PO4) => H3PO4 + 3 NH3 = ((NH4)3PO4)
C4H8 + O2 = CO2 + H2O => C4H8 + 6 O2 = 4 CO2 + 4 H2O
Fe + H2O = Fe3O4 + H2 => 3 Fe + 4 H2O = Fe3O4 + 4 H2
BF3 + Li2SO3 = B2(SO3)3 + LiF => 2 BF3 + 3 Li2SO3 = B2(SO3)3 + 6 LiF
C4H10 + O2 = CO2 + H2O => 2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
Fe2(SO4)3 + KOH = K2SO4 + Fe(OH)3 => Fe2(SO4)3 + 6 KOH = 3 K2SO4 + 2 Fe(OH)3
N2H4(l) = NH3(g) + N2(g) => 3 N2H4(l) = 4 NH3(g) + N2(g)
Fe2O3 + CO = Fe + CO2 => Fe2O3 + 3 CO = 2 Fe + 3 CO2
FeI2 = Fe + I2 => FeI2 = Fe + I2
H2SO4 + Al(OH)3 = Al2(SO4)3 + H2O => 3 H2SO4 + 2 Al(OH)3 = Al2(SO4)3 + 6 H2O
Cl2(g) + NH3(aq) = NH4Cl(aq) + N2(g) => 3 Cl2(g) + 8 NH3(aq) = 6 NH4Cl(aq) + N2(g)
Pb(NO3)2 + BaCl2 = PbCl2 + Ba(NO3)2 => Pb(NO3)2 + BaCl2 = PbCl2 + Ba(NO3)2
NaBr + AgNO3 = NaNO3 + AgBr => NaBr + AgNO3 = NaNO3 + AgBr
Ag2CO3 = Ag + CO2 + O2 => 2 Ag2CO3 = 4 Ag + 2 CO2 + O2
Al + HCl = AlCl + H2 => 2 Al + 2 HCl = 2 AlCl + H2
SnCl2 + K2CrO7 + HCl = SnCl4 + CrCl3 + KCl + H2O => 9 SnCl2 + 2 K2CrO7 + 28 HCl = 9 SnCl4 + 2 CrCl3 + 4 KCl + 14 H2O
Balance equation of any chemical reaction online for freeEquations balanced on 01/06/19 Equations balanced on 12/14/18 Equations balanced on 01/13/18
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