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Chemical Equations Balanced on 12/31/19

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Balance equation of any chemical reaction online for free
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Al + GeO2 = Al2O3 + Ge =>
4 Al + 3 GeO2 = 2 Al2O3 + 3 Ge

PbCl2 + H2O = PbO + HCl =>
PbCl2 + H2O = PbO + 2 HCl

Li + H2O = LiOH + H2 =>
2 Li + 2 H2O = 2 LiOH + H2

Al + KSCN + HCl = KCl + AlCl3 + NH4Cl + C + H2S =>
4 Al + 3 KSCN + 18 HCl = 3 KCl + 4 AlCl3 + 3 NH4Cl + 3 C + 3 H2S

MnO4{-} + C2O4{2-} + H{+} = Mn{2+} + CO2 + H2O =>
2 MnO4{-} + 5 C2O4{2-} + 16 H{+} = 2 Mn{2+} + 10 CO2 + 8 H2O

Zn + CuSO4 = ZnSO4 + Cu =>
Zn + CuSO4 = ZnSO4 + Cu

MnO4{-} + ClO3{-} + H{+} = ClO4{-} + Mn{2+} + H2O =>
2 MnO4{-} + 5 ClO3{-} + 6 H{+} = 5 ClO4{-} + 2 Mn{2+} + 3 H2O

Mg + H2O = Mg(OH)2 + H2 =>
Mg + 2 H2O = Mg(OH)2 + H2

As2O3 + HIO3 + H2O = H3AsO4 + I2 =>
5 As2O3 + 4 HIO3 + 13 H2O = 10 H3AsO4 + 2 I2

As2O3 + HIO3 + H2O = H3AsO4 + I2 =>
5 As2O3 + 4 HIO3 + 13 H2O = 10 H3AsO4 + 2 I2

Fe + AgNO3 = Fe(NO3)2 + Ag =>
Fe + 2 AgNO3 = Fe(NO3)2 + 2 Ag

BaCrO4 + KI + HCl = BaCl2 + CrCl3 + KCl + H2O + I2 =>
2 BaCrO4 + 6 KI + 16 HCl = 2 BaCl2 + 2 CrCl3 + 6 KCl + 8 H2O + 3 I2

BaCrO4 + KI + HCl = BaCl2 + CrCl3 + KCl + H2O + I2 =>
2 BaCrO4 + 6 KI + 16 HCl = 2 BaCl2 + 2 CrCl3 + 6 KCl + 8 H2O + 3 I2

BaCrO4 + KI + HCl = BaCl2 + CrCl3 + KCl4 + H2O + I2 =>
8 BaCrO4 + 6 KI + 64 HCl = 8 BaCl2 + 8 CrCl3 + 6 KCl4 + 32 H2O + 3 I2

BaCrO4 + KI + HCl = BaCl2 + CrCl3 + KCl4 + H2O + I2 =>
8 BaCrO4 + 6 KI + 64 HCl = 8 BaCl2 + 8 CrCl3 + 6 KCl4 + 32 H2O + 3 I2

Na + Cl2 = NaCl =>
2 Na + Cl2 = 2 NaCl

FeCl2 + Cl2 = FeCl3 =>
2 FeCl2 + Cl2 = 2 FeCl3

Na3PO3(aq) + CaCl2(aq) = Ca3(PO3)2 + NaCl =>
2 Na3PO3(aq) + 3 CaCl2(aq) = Ca3(PO3)2 + 6 NaCl

C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O

K2CrO4 + AgNO3 = Ag2CrO4 + KNO3 =>
K2CrO4 + 2 AgNO3 = Ag2CrO4 + 2 KNO3

CuSCN + KIO3 + HCl = CuSO4 + KCl + HCN + ICl + H2O =>
4 CuSCN + 7 KIO3 + 14 HCl = 4 CuSO4 + 7 KCl + 4 HCN + 7 ICl + 5 H2O

SO2 + O2 = SO3 =>
2 SO2 + O2 = 2 SO3

Co + O2 = CoO =>
2 Co + O2 = 2 CoO

NO + H2SO4 + KMnO4 = HNO3 + K2SO4 + MnSO4 + H2O =>
10 NO + 9 H2SO4 + 6 KMnO4 = 10 HNO3 + 3 K2SO4 + 6 MnSO4 + 4 H2O

Cl2 + CrI3 + KOH = K2CrO4 + KIO3 + KCl + H2O =>
21 Cl2 + 2 CrI3 + 52 KOH = 2 K2CrO4 + 6 KIO3 + 42 KCl + 26 H2O

Al + O2 = Al2O3 =>
4 Al + 3 O2 = 2 Al2O3

Al + O2 = Al2O3 =>
4 Al + 3 O2 = 2 Al2O3

Al + O2 = Al2O3 =>
4 Al + 3 O2 = 2 Al2O3

Al + O2 = Al2O3 =>
4 Al + 3 O2 = 2 Al2O3

Ni + O2 = NiO =>
2 Ni + O2 = 2 NiO

Zn + O2 = ZnO =>
2 Zn + O2 = 2 ZnO

C2H4O + O2 = CO2 + H2O =>
2 C2H4O + 5 O2 = 4 CO2 + 4 H2O

KNO3 + S = SO2 + K2O + NO =>
4 KNO3 + 3 S = 3 SO2 + 2 K2O + 4 NO

HCl + Ca(OH)2 = CaCl2 + H2O =>
2 HCl + Ca(OH)2 = CaCl2 + 2 H2O

C2H2 + O2 = CO2 + H2O =>
2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

KMnO4 + SO2 + H2O = K2SO4 + MnSO4 + H2SO4 =>
2 KMnO4 + 5 SO2 + 2 H2O = K2SO4 + 2 MnSO4 + 2 H2SO4

Al + N2 = AlN =>
2 Al + N2 = 2 AlN

Al + N2 = AlN =>
2 Al + N2 = 2 AlN

Cu + H2SO4 = CuSO4 + H2O + SO2 =>
Cu + 2 H2SO4 = CuSO4 + 2 H2O + SO2

Cu + H2SO4 = CuSO4 + H2O + SO2 =>
Cu + 2 H2SO4 = CuSO4 + 2 H2O + SO2

(NH4)HCO3 + NaCl = NH4Cl + NaHCO3 =>
(NH4)HCO3 + NaCl = NH4Cl + NaHCO3

Fe + AgNO3 = Fe(NO3)2 + Ag =>
Fe + 2 AgNO3 = Fe(NO3)2 + 2 Ag

Na2WO4*2H2O + Na2HPO4 + Na2MoO4*2H2O + H2SO4 = H3PW7Mo5O40 + NaHSO4 + H2O =>
7 Na2WO4*2H2O + Na2HPO4 + 5 Na2MoO4*2H2O + 26 H2SO4 = H3PW7Mo5O40 + 26 NaHSO4 + 36 H2O

Na2WO4*2H2O + Na2HPO4 + Na2MoO4*2H2O + H2SO4 = H3PW6Mo6O40 + NaHSO4 + H2O =>
6 Na2WO4*2H2O + Na2HPO4 + 6 Na2MoO4*2H2O + 26 H2SO4 = H3PW6Mo6O40 + 26 NaHSO4 + 36 H2O

Na2WO4*2H2O + Na2HPO4 + Na2MoO4*2H2O + H2SO4 = H3PW5Mo7O40 + NaHSO4 + H2O =>
5 Na2WO4*2H2O + Na2HPO4 + 7 Na2MoO4*2H2O + 26 H2SO4 = H3PW5Mo7O40 + 26 NaHSO4 + 36 H2O

Na2WO4*2H2O + Na2HPO4 + Na2MoO4*2H2O + H2SO4 = H3PW6Mo6O40 + NaHSO4 + H2O =>
6 Na2WO4*2H2O + Na2HPO4 + 6 Na2MoO4*2H2O + 26 H2SO4 = H3PW6Mo6O40 + 26 NaHSO4 + 36 H2O

Fe + AgNO3 = Fe(NO3)2 + Ag =>
Fe + 2 AgNO3 = Fe(NO3)2 + 2 Ag

K2CrO4 + AgNO3 = Ag2CrO4 + KNO3 =>
K2CrO4 + 2 AgNO3 = Ag2CrO4 + 2 KNO3

HCl + CaCO3 = CaCl2 + H2O + CO2 =>
2 HCl + CaCO3 = CaCl2 + H2O + CO2

P + Br = PBr3 =>
P + 3 Br = PBr3

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Balance equation of any chemical reaction online for free
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Equations balanced on 12/24/19
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Equations balanced on 12/31/18
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