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Chemical Equations Balanced on 12/28/20

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Balance equation of any chemical reaction online for free
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Fe2O3 + CO = Fe + CO2 =>
Fe2O3 + 3 CO = 2 Fe + 3 CO2

K2CO3 + (NH4)2HPO4 + Fe2O3 = K733Fe1000(PO4)1200O66 + CO2 + NH3 + H2O + O2 =>
1466.0000000004K2CO3 + 4800.0000000013(NH4)2HPO4 + 2000.0000000005Fe2O3 = 4.0000000000011K733Fe1000(PO4)1200O66 + 1466.0000000004CO2 + 9600.0000000026NH3 + 7200.000000002H2O + O2

Al2(CO3)3 + Mg(OH)2 = Al(OH)3 + MgCO3 =>
Al2(CO3)3 + 3 Mg(OH)2 = 2 Al(OH)3 + 3 MgCO3

PB(NO3)2 + KCl = PBCl2 + KNO3 =>
PB(NO3)2 + 2 KCl = PBCl2 + 2 KNO3

S2 + O2 = SO2 =>
S2 + 2 O2 = 2 SO2

CO2 + H2O = C6H12O6 + O2 =>
6 CO2 + 6 H2O = C6H12O6 + 6 O2

NaClO + HCl = NaCl + H2O + Cl2 =>
NaClO + 2 HCl = NaCl + H2O + Cl2

C5H12 + O2 = CO2 + H2O =>
C5H12 + 8 O2 = 5 CO2 + 6 H2O

H2SO4 + KOH = K2SO4 + H2O =>
H2SO4 + 2 KOH = K2SO4 + 2 H2O

Cr2O7{-2} + H{+} + {-} = Cr{+3} + H2O =>
Cr2O7{-2} + 14 H{+} + 6e = 2 Cr{+3} + 7 H2O

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

Ca(OH)2 + HNO3 = Ca(NO3)2 + H2O =>
Ca(OH)2 + 2 HNO3 = Ca(NO3)2 + 2 H2O

KMnO4 + SO2 + H2O = K2SO4 + MnSO4 + H2SO4 =>
2 KMnO4 + 5 SO2 + 2 H2O = K2SO4 + 2 MnSO4 + 2 H2SO4

PbS + O2 = PbO + SO2 =>
2 PbS + 3 O2 = 2 PbO + 2 SO2

K2Cl2O7 + SO2 + H2SO4 = K2SO4 + Cl2(SO4)3 + H2O =>
K2Cl2O7 + 3 SO2 + H2SO4 = K2SO4 + Cl2(SO4)3 + H2O

FeS2 + O2 = Fe2O3 + SO2 =>
4 FeS2 + 11 O2 = 2 Fe2O3 + 8 SO2

NaOH + Cl2 = NaCl + NaClO + H2O =>
2 NaOH + Cl2 = NaCl + NaClO + H2O

CO + H2 = C8H18 + H2O =>
8 CO + 17 H2 = C8H18 + 8 H2O

CO + H2 = C8H18 + H2O =>
8 CO + 17 H2 = C8H18 + 8 H2O

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O

Cr2O7{-2} + H{+} + {-} = Cr{+3} + H2O =>
Cr2O7{-2} + 14 H{+} + 6e = 2 Cr{+3} + 7 H2O

NH4NO3 = N2 + O2 + H2O =>
2 NH4NO3 = 2 N2 + O2 + 4 H2O

NH4NO3 = N2 + O2 + H2O =>
2 NH4NO3 = 2 N2 + O2 + 4 H2O

CuO + HNO3 = Cu(NO3)2 + H2O =>
CuO + 2 HNO3 = Cu(NO3)2 + H2O

KCN + HCl = KCl + HCN =>
KCN + HCl = KCl + HCN

Cr2O7{-2} + H2S + H{+} = Cr{+3} + S + H2O =>
Cr2O7{-2} + 3 H2S + 8 H{+} = 2 Cr{+3} + 3 S + 7 H2O

Fe + O2 = Fe3O4 =>
3 Fe + 2 O2 = Fe3O4

Fe + H2O = Fe3O4 + H2 =>
3 Fe + 4 H2O = Fe3O4 + 4 H2

Pb(N3)2 + Cr(MnO4)2 = Cr2O3 + MnO2 + Pb3O4 + NO =>
15 Pb(N3)2 + 44 Cr(MnO4)2 = 22 Cr2O3 + 88 MnO2 + 5 Pb3O4 + 90 NO

Pb(N3)2 + Cr(MnO4)2 = Cr2O3 + MnO2 + Pb3O4 + NO =>
15 Pb(N3)2 + 44 Cr(MnO4)2 = 22 Cr2O3 + 88 MnO2 + 5 Pb3O4 + 90 NO

(NH4)2Cr2O7 = Cr2O3 + N2 + H2O =>
(NH4)2Cr2O7 = Cr2O3 + N2 + 4 H2O

Zn + H2SO4 + K2Cr2O7 = KCr(SO4) + ZnSO4 + H2O =>
5 Zn + 7 H2SO4 + K2Cr2O7 = 2 KCr(SO4) + 5 ZnSO4 + 7 H2O

PbO2 + HCl = PbCl2 + Cl2 + H2O =>
PbO2 + 4 HCl = PbCl2 + Cl2 + 2 H2O

SbCl3 + KMnO4 + HCl = SbCl5 + MnCl2 + KCl + H2O =>
5 SbCl3 + 2 KMnO4 + 16 HCl = 5 SbCl5 + 2 MnCl2 + 2 KCl + 8 H2O

Ce + H2SO4 = Ce2(SO4)3 + H2 =>
2 Ce + 3 H2SO4 = Ce2(SO4)3 + 3 H2

(NH4)2S + HCl = NH4Cl + H2S =>
(NH4)2S + 2 HCl = 2 NH4Cl + H2S

SbCl3 + KMnO4 + HCl = SbCl5 + MnCl2 + KCl + H2O =>
5 SbCl3 + 2 KMnO4 + 16 HCl = 5 SbCl5 + 2 MnCl2 + 2 KCl + 8 H2O

Cl2O7 + H2O = HClO4 =>
Cl2O7 + H2O = 2 HClO4

K2CO3 + (NH4)2HPO4 + Fe2O3 = K733Fe10(PO4)12O066 + CO2 + NH3 + H2O + O2 =>
1466 K2CO3 + 48(NH4)2HPO4 + 20 Fe2O3 = 4 K733Fe10(PO4)12O066 + 1466 CO2 + 96 NH3 + 72 H2O + 595 O2

Cl2O7 = Cl2 + O2 =>
2 Cl2O7 = 2 Cl2 + 7 O2

ZnCl2 + Na2CO3 = ZnCO3 + NaCl =>
ZnCl2 + Na2CO3 = ZnCO3 + 2 NaCl

K2CO3 + (NH4)2HPO4 + Fe2O3 = K733Fe1000(PO4)1200O66 + CO2 + NH3 + H2O + O2 =>
1466.0000000004K2CO3 + 4800.0000000013(NH4)2HPO4 + 2000.0000000005Fe2O3 = 4.0000000000011K733Fe1000(PO4)1200O66 + 1466.0000000004CO2 + 9600.0000000026NH3 + 7200.000000002H2O + O2

C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O

Pb + H2O = Pb(OH)2 + H2 =>
Pb + 2 H2O = Pb(OH)2 + H2

Al2(SO4)3 + NaOH = Al(OH)3 + Na2SO4 =>
Al2(SO4)3 + 6 NaOH = 2 Al(OH)3 + 3 Na2SO4

CH4 + O2 = CO2 + H2O =>
CH4 + 2 O2 = CO2 + 2 H2O

CH4 + O2 = CO2 + H2O =>
CH4 + 2 O2 = CO2 + 2 H2O

SO2 + O2 + H2O = H2SO4 =>
2 SO2 + O2 + 2 H2O = 2 H2SO4

MgSO4 + Na2CO3 = MgCO3 + Na2SO4 =>
MgSO4 + Na2CO3 = MgCO3 + Na2SO4

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Balance equation of any chemical reaction online for free
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Equations balanced on 12/21/20
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Equations balanced on 12/28/19
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