Equations balanced on the previous day | Equations balanced on the next day |
4 Cr + 7 SnCl4 = 7 Sn + 4 CrCl7
SnCl2 + HgCl3 = SnCl4 + HgCl =>
SnCl2 + HgCl3 = SnCl4 + HgCl
Cr + SnCl4 = Sn + CrCl7 =>
4 Cr + 7 SnCl4 = 7 Sn + 4 CrCl7
Ti2(SO4)4 + CrCl3 = TiCl4 + Cr2(SO4)3 =>
3 Ti2(SO4)4 + 8 CrCl3 = 6 TiCl4 + 4 Cr2(SO4)3
HCl + CuCo3 = HClCuCo3 =>
HCl + CuCo3 = HClCuCo3
Pb(s) + PbO2(s) + H2SO4(aq) = PbSO4(s) + H2O(t) =>
Pb(s) + PbO2(s) + 2 H2SO4(aq) = 2 PbSO4(s) + 2 H2O(t)
Fe + H2O + O2 = Fe2O3H2O =>
4 Fe + 2 H2O + 3 O2 = 2 Fe2O3H2O
CH4H10 + O2 = CO + water =>
CH4H10 + 4 O2 = CO + 7 H2O
Na2HPO4 + (NH4)6Mo7O24 + HNO3 = (NH4)3PMo12O40 + NaNO3 + NH4NO3 + H2O =>
7 Na2HPO4 + 12(NH4)6Mo7O24 + 65 HNO3 = 7(NH4)3PMo12O40 + 14 NaNO3 + 51 NH4NO3 + 36 H2O
NH4Br + KNO3 = KBr + NH4NO3 =>
NH4Br + KNO3 = KBr + NH4NO3
CuO + HNO3*2H2O + NH4OH*2H2O = [Cu(NH3)4](NO3)2 + H2O =>
CuO + 2 HNO3*2H2O + 4 NH4OH*2H2O = [Cu(NH3)4](NO3)2 + 17 H2O
C2H6 + O2 = CO + H2O =>
2 C2H6 + 5 O2 = 4 CO + 6 H2O
GdO + CO2 = GdCO2 + O =>
GdO + CO2 = GdCO2 + O
KI + KBrO3 + HCl = KCl + H2O + KBr + I2 =>
6 KI + KBrO3 + 6 HCl = 6 KCl + 3 H2O + KBr + 3 I2
H3PO4 + NaOH = PO4Na + H4O =>
H3PO4 + NaOH = PO4Na + H4O
PbSO4 + NaCO3 = NaSO4 + PbCO3 =>
PbSO4 + NaCO3 = NaSO4 + PbCO3
Cr + SnCl4 = Sn + CrCl7 =>
4 Cr + 7 SnCl4 = 7 Sn + 4 CrCl7
C20H12 + H2O = CO2 + H2 =>
C20H12 + 40 H2O = 20 CO2 + 46 H2
Cu{2+}(aq) + I{-}(aq) = CuI(s) + I2(aq) =>
2 Cu{2+}(aq) + 4 I{-}(aq) = 2 CuI(s) + I2(aq)
Cl(g) + NH3 = N2(g) + NH4Cl =>
6 Cl(g) + 8 NH3 = N2(g) + 6 NH4Cl
Fl + H2O = HFl + O2 =>
4 Fl + 2 H2O = 4 HFl + O2
K2Cr2O7 + Ni(NO3)3 = KNO3 + Ni2(Cr2O7)3 =>
3 K2Cr2O7 + 2 Ni(NO3)3 = 6 KNO3 + Ni2(Cr2O7)3
Al2 + Se3 = Al2Se3 =>
Al2 + Se3 = Al2Se3
H2O + H2BO3 = BH4 + OH =>
5 H2O + H2BO3 = BH4 + 8 OH
CO2 + H2O = C14H3O + O2 =>
56 CO2 + 6 H2O = 4 C14H3O + 57 O2
Cu2OH2CO3 + O2 = CuO + CO2 + H2O =>
2 Cu2OH2CO3 + O2 = 4 CuO + 2 CO2 + 2 H2O
K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O
S + KClO3 + H2O = Cl2 + H2SO4 + KOH =>
5 S + 6 KClO3 + 8 H2O = 3 Cl2 + 5 H2SO4 + 6 KOH
CH3CH2OH + K2Cr2O7 + H2SO4 = H2O + CH3COH + Cr2(SO4) + K2SO4 =>
5 CH3CH2OH + K2Cr2O7 + 2 H2SO4 = 7 H2O + 5 CH3COH + Cr2(SO4) + K2SO4
Cu2OH2CO3 + O2 = CuO + CO2 + H2O =>
2 Cu2OH2CO3 + O2 = 4 CuO + 2 CO2 + 2 H2O
C3H7CHO + K2Cr2O7 + H2SO4 = Cr2(SO4)3 + H2O + C2H5COOH + K2SO4 =>
9 C3H7CHO + 5 K2Cr2O7 + 20 H2SO4 = 5 Cr2(SO4)3 + 20 H2O + 12 C2H5COOH + 5 K2SO4
Cu2OH2CO3 + O2 = CuO + CO2 + H2O =>
2 Cu2OH2CO3 + O2 = 4 CuO + 2 CO2 + 2 H2O
Cr2(CO3)3 + H3AsO4 = CrAsO4 + H2O + CO2 =>
Cr2(CO3)3 + 2 H3AsO4 = 2 CrAsO4 + 3 H2O + 3 CO2
CO2 + H2O = C14H3O + O2 =>
56 CO2 + 6 H2O = 4 C14H3O + 57 O2
C6H12O2 + O2 = CO2 + H2O(g) =>
C6H12O2 + 8 O2 = 6 CO2 + 6 H2O(g)
CO2 + H2O = C14H3O + O2 =>
56 CO2 + 6 H2O = 4 C14H3O + 57 O2
C2H4 + Br2 + Cl = C2H4ClBr =>
2 C2H4 + Br2 + 2 Cl = 2 C2H4ClBr
CO2 + H2O = C14H3O + O2 =>
56 CO2 + 6 H2O = 4 C14H3O + 57 O2
CO2 + H2O = C14H3O + O2 =>
56 CO2 + 6 H2O = 4 C14H3O + 57 O2
CO2 + H2O = C14H3O + O2 =>
56 CO2 + 6 H2O = 4 C14H3O + 57 O2
CH3CH2OH + K2Cr2O7 + H2SO4 = H2O + CH3COH + Cr2(SO4) + K2SO4 =>
5 CH3CH2OH + K2Cr2O7 + 2 H2SO4 = 7 H2O + 5 CH3COH + Cr2(SO4) + K2SO4
NaOH + HCI = H2O + NaCI =>
NaOH + HCI = H2O + NaCI
Mg(s) + HCl(aq) = H2(g) + MgCl2(aq) =>
Mg(s) + 2 HCl(aq) = H2(g) + MgCl2(aq)
[Ag(NH3)2]NO3 + KCN = [Ag(NH3)2]CN + KNO3 =>
[Ag(NH3)2]NO3 + KCN = [Ag(NH3)2]CN + KNO3
CO2 + H2O = C14H3O + O2 =>
56 CO2 + 6 H2O = 4 C14H3O + 57 O2
Cu2OH2CO3 + O2 = CuO + CO2 + H2O =>
2 Cu2OH2CO3 + O2 = 4 CuO + 2 CO2 + 2 H2O
NaClO4 = NaCl + O2 =>
NaClO4 = NaCl + 2 O2
Cu2OH2CO3 + O2 = CuO + CO2 + H2O =>
2 Cu2OH2CO3 + O2 = 4 CuO + 2 CO2 + 2 H2O
H2S + O = H2O + S =>
H2S + O = H2O + S
CO2 + H2O = C14H3O + O2 =>
56 CO2 + 6 H2O = 4 C14H3O + 57 O2
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/18/23
Equations balanced on 12/18/22
-donnez-nous vos commentaires de votre expérience avec l'équilibreur d'équation chimique.