| Équations équilibrées la veille | Équations équilibrées le lendemain |
FeTiO3 + 2 H2SO4 + 5 H2O = FeSO4*7H2O + TiSO5
VO2{+} + SO2 + H{+} = VO{2+} + HSO4{-} =>
2 VO2{+} + SO2 + H{+} = 2 VO{2+} + HSO4{-}
CH3COOH + CaCO3 = CO2 + Ca(C2H3O2)2 + H2O =>
2 CH3COOH + CaCO3 = CO2 + Ca(C2H3O2)2 + H2O
CH3OH + K2Cr2O7 + H2SO4 = Cr2(SO4)3 + K2SO4 + CH3COCH3 + H2O =>
9 CH3OH + K2Cr2O7 + 4 H2SO4 = Cr2(SO4)3 + K2SO4 + 3 CH3COCH3 + 13 H2O
NH4OH + KMnO4 + H2SO4 = N2 + K2SO4 + MnSO4 + H2O =>
10 NH4OH + 6 KMnO4 + 9 H2SO4 = 5 N2 + 3 K2SO4 + 6 MnSO4 + 34 H2O
Pt + HCl + HNO3 = H2PtCl6 + NO2 + H2O =>
Pt + 6 HCl + 4 HNO3 = H2PtCl6 + 4 NO2 + 4 H2O
MgH2 + O2 = MgO2 + H2O =>
2 MgH2 + 3 O2 = 2 MgO2 + 2 H2O
PbO2(s) + HCl = PbCl2(s) + Cl2 + H2O =>
PbO2(s) + 4 HCl = PbCl2(s) + Cl2 + 2 H2O
Cu3AsS4 + H2O + CuSO4 = H3AsO3 + CuS + H2SO4 =>
8 Cu3AsS4 + 20 H2O + 9 CuSO4 = 8 H3AsO3 + 33 CuS + 8 H2SO4
H2O + Fe = FeOOH + H =>
2 H2O + Fe = FeOOH + 3 H
Cu3AsS4 + CuSO4 + H2O = Cu9S5 + H3AsO3 + H2SO4 =>
16 Cu3AsS4 + 51 CuSO4 + 84 H2O = 11 Cu9S5 + 16 H3AsO3 + 60 H2SO4
KBr + H2SO4 = Br + K2SO4 + H2O + SO2 =>
2 KBr + 2 H2SO4 = 2 Br + K2SO4 + 2 H2O + SO2
HCl + Ni2(CO3)3 = NiCl3 + CO2 + H2O =>
6 HCl + Ni2(CO3)3 = 2 NiCl3 + 3 CO2 + 3 H2O
Cu3AsS4 + H2O + CuSO4 = H3AsO3 + CuS + H2SO4 =>
8 Cu3AsS4 + 20 H2O + 9 CuSO4 = 8 H3AsO3 + 33 CuS + 8 H2SO4
In(s) + H2So4(aq) = In(So4)(aq) + H2(g) =>
In(s) + H2So4(aq) = In(So4)(aq) + H2(g)
Cu3AsS4 + H2O + CuSO4 = H3AsO3 + CuS + H2SO4 =>
8 Cu3AsS4 + 20 H2O + 9 CuSO4 = 8 H3AsO3 + 33 CuS + 8 H2SO4
Fe2(SO4)3 + KX = K3FeX6 + K2SO4 =>
Fe2(SO4)3 + 12 KX = 2 K3FeX6 + 3 K2SO4
Cu3AsS4 + H2O + CuSO4 = H3AsO3 + CuS + H2SO4 =>
8 Cu3AsS4 + 20 H2O + 9 CuSO4 = 8 H3AsO3 + 33 CuS + 8 H2SO4
Br2{+} + OH{-} = BrO3{-} + Br{-} + H2O =>
2 Br2{+} + 6 OH{-} = BrO3{-} + 3 Br{-} + 3 H2O
Fe + S8(s) = FeS(s) =>
8 Fe + S8(s) = 8 FeS(s)
HgNO3 + HNO3 + C2H6O = Hg(ONC)2 + H2O + CO2 =>
4 HgNO3 + 4 HNO3 + 5 C2H6O = 4 Hg(ONC)2 + 17 H2O + 2 CO2
K + Cr = K3Cr =>
3 K + Cr = K3Cr
C6H12N2 + H2O = C3H6O + N2H4 =>
C6H12N2 + 2 H2O = 2 C3H6O + N2H4
CH3CH2CH3OH + Na2Cr2O7 + H2SO4 = CH3COCH3 + Na2SO4 + Cr2(SO4)3 + H2O =>
2 CH3CH2CH3OH + Na2Cr2O7 + 4 H2SO4 = 2 CH3COCH3 + Na2SO4 + Cr2(SO4)3 + 7 H2O
SnCl2 + KMnO4 + H2SO4 = SnCl4 + MnSO4 + K2SO4 + H2O + Sn(SO4)2 =>
10 SnCl2 + 4 KMnO4 + 16 H2SO4 = 5 SnCl4 + 4 MnSO4 + 2 K2SO4 + 16 H2O + 5 Sn(SO4)2
C6H12N2 + H2O = C3H6O + N2H4 =>
C6H12N2 + 2 H2O = 2 C3H6O + N2H4
As + HNO3 + H2O = H3AsO4 + N =>
As + HNO3 + H2O = H3AsO4 + N
Cu3AsS4 + H2O + CuSO4 = H3AsO3 + CuS + H2SO4 =>
8 Cu3AsS4 + 20 H2O + 9 CuSO4 = 8 H3AsO3 + 33 CuS + 8 H2SO4
HNO3 + ClO2 = NO + ClO3 + H2O =>
2 HNO3 + 3 ClO2 = 2 NO + 3 ClO3 + H2O
SeO3 + H2O = SeO2 + H2O2 =>
SeO3 + H2O = SeO2 + H2O2
C6H12N2 + H2O = C3H6O + N2H4 =>
C6H12N2 + 2 H2O = 2 C3H6O + N2H4
K2CrO4 + Cu(NO3)2 = K(NO3) + Cu(CrO4) =>
K2CrO4 + Cu(NO3)2 = 2 K(NO3) + Cu(CrO4)
MnSO3 + NaBiO3 + HNO2 = Bi(NO2)3 + HMnO4 + Na2SO3 + NaNO2 + H2O =>
2 MnSO3 + 5 NaBiO3 + 16 HNO2 = 5 Bi(NO2)3 + 2 HMnO4 + 2 Na2SO3 + NaNO2 + 7 H2O
TbCl3 + H2O = Tb(OH)3 + HCl =>
TbCl3 + 3 H2O = Tb(OH)3 + 3 HCl
Ag + CuBr = AgBr + Cu =>
Ag + CuBr = AgBr + Cu
NH4NO3 = N2 + H2O + HNO4 =>
7 NH4NO3 = 6 N2 + 13 H2O + 2 HNO4
C6H12N2 + H2O = C3H6O + N2H4 =>
C6H12N2 + 2 H2O = 2 C3H6O + N2H4
Li(OH)2 + Be(OH)2 = LiBeO2 + H2O =>
Li(OH)2 + Be(OH)2 = LiBeO2 + 2 H2O
NH4H2PO4 + NaCl = NH3 + HCl + Na3PO4 =>
NH4H2PO4 + 3 NaCl = NH3 + 3 HCl + Na3PO4
[Ni(NH3)6]Cl2 + KCN = Ni(CN)4 + K + Cl2 + NH3 =>
[Ni(NH3)6]Cl2 + 4 KCN = Ni(CN)4 + 4 K + Cl2 + 6 NH3
H2O + ClO3 + B = Cl2 + B(OH)3 =>
6 H2O + 2 ClO3 + 4 B = Cl2 + 4 B(OH)3
Cu(OH)2 + HCH3COO = Cu(CH3COO)2 + H2O =>
Cu(OH)2 + 2 HCH3COO = Cu(CH3COO)2 + 2 H2O
Ca(OH)2 + H2SO4 = HOH + Ca2(SO4)2 =>
2 Ca(OH)2 + 2 H2SO4 = 4 HOH + Ca2(SO4)2
[(OH)3IO3]{2-} + H3O{+} = IO4{-} + H2O =>
[(OH)3IO3]{2-} + H3O{+} = IO4{-} + 3 H2O
KClO3 + SO2 = K2SO4 + ClO2 =>
2 KClO3 + SO2 = K2SO4 + 2 ClO2
C3H10 + O2 = C02 + H2O =>
2 C3H10 + 5 O2 = 3 C02 + 10 H2O
NH4Cl(s) + O2 = HNO2 + HCl + H2O =>
2 NH4Cl(s) + 3 O2 = 2 HNO2 + 2 HCl + 2 H2O
Mg(s) + HC2H3O2(aq) = Mg(C2H3O2)2(aq) + H2(s) =>
Mg(s) + 2 HC2H3O2(aq) = Mg(C2H3O2)2(aq) + H2(s)
Na4Cl = Na + Cl2 =>
2 Na4Cl = 8 Na + Cl2
[(OH)3IO3]{2-} + H3O{+} = IO4{-} + H2O =>
[(OH)3IO3]{2-} + H3O{+} = IO4{-} + 3 H2O
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| Équations équilibrées la veille | Équations équilibrées le lendemain |
Équations équilibrées sur11/27/23
Équations équilibrées sur12/27/22
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