| Équations équilibrées la veille | Équations équilibrées le lendemain |
2 BN + TiC = TiB2 + C + N2
Li2SO3 + K2Cr2O7 + H2SO4 = Li2SO4 + Cr2(SO4)3 + K2SO4 + H2O =>
3 Li2SO3 + K2Cr2O7 + 4 H2SO4 = 3 Li2SO4 + Cr2(SO4)3 + K2SO4 + 4 H2O
C10H5O + C2H5I = I2 + H2O + C2H4 =>
2 C10H5O + 34 C2H5I = 17 I2 + 2 H2O + 44 C2H4
SiO2 + LiOH = Li2SiO3 + H2O =>
SiO2 + 2 LiOH = Li2SiO3 + H2O
NO3{-} + H2O + OH{-} + Al = NH3 + AlO2{-} =>
3 NO3{-} + 2 H2O + 5 OH{-} + 8 Al = 3 NH3 + 8 AlO2{-}
NaBiO3 + MnCl2 + HNO3 = Bi(NO3)3 + HMnO4 + NaNO3 + NaCl + H2O =>
5 NaBiO3 + 2 MnCl2 + 16 HNO3 = 5 Bi(NO3)3 + 2 HMnO4 + NaNO3 + 4 NaCl + 7 H2O
NO3{-} + H2O + OH{-} + Al = NH3 + AlO2{-} =>
3 NO3{-} + 2 H2O + 5 OH{-} + 8 Al = 3 NH3 + 8 AlO2{-}
C3H3O2Na + O2 = Na2CO3 + CO2 + H2O =>
2 C3H3O2Na + 6 O2 = Na2CO3 + 5 CO2 + 3 H2O
HI(aq) + NaOH(aq) = NaI + H2O =>
HI(aq) + NaOH(aq) = NaI + H2O
CH2(NH2)COOH + O2 = N2 + CO2 + H2O =>
4 CH2(NH2)COOH + 9 O2 = 2 N2 + 8 CO2 + 10 H2O
P4 + JO3{-} + OH{-} = PO4{3-} + J2 + H2O =>
P4 + 4 JO3{-} + 8 OH{-} = 4 PO4{3-} + 2 J2 + 4 H2O
Cr(s) + NO{3}{-}(aq) = Cr{3}{+}(aq) + NO(g) =>
Cr(s) + NO{3}{-}(aq) = Cr{3}{+}(aq) + NO(g)
Na(HCO3) + HCl = NaCl + CO2 + H2O =>
Na(HCO3) + HCl = NaCl + CO2 + H2O
Na2SO3 + H2O + Cl2 = Na2SO4 + HCl =>
Na2SO3 + H2O + Cl2 = Na2SO4 + 2 HCl
NaNO3 + H2SO4 + FeSO4 = NO2 + Fe2(SO4)3 + H2O + Na2SO4 =>
2 NaNO3 + 2 H2SO4 + 2 FeSO4 = 2 NO2 + Fe2(SO4)3 + 2 H2O + Na2SO4
Pb(NO3) + S(PO4) = Pb(PO4) + S(NO3) =>
Pb(NO3) + S(PO4) = Pb(PO4) + S(NO3)
P4 + JO3{-} + OH{-} = PO4{3-} + J2 + H2O =>
P4 + 4 JO3{-} + 8 OH{-} = 4 PO4{3-} + 2 J2 + 4 H2O
Fe2O3(s) + NaCl(l) = FeCl3(s) + Na2O =>
Fe2O3(s) + 6 NaCl(l) = 2 FeCl3(s) + 3 Na2O
P4 + JO3{-} + OH{-} = PO4{3-} + J2 + H2O =>
P4 + 4 JO3{-} + 8 OH{-} = 4 PO4{3-} + 2 J2 + 4 H2O
K2CrO7 + FeCl2 + HCl = CrCl3 + FeCl4 + KCl + H2O =>
2 K2CrO7 + 9 FeCl2 + 28 HCl = 2 CrCl3 + 9 FeCl4 + 4 KCl + 14 H2O
WS3 + CaO = CaS + W + O2 =>
2 WS3 + 6 CaO = 6 CaS + 2 W + 3 O2
H2SO4 + BaCl2 = Ba2(SO4)2 + HCl =>
2 H2SO4 + 2 BaCl2 = Ba2(SO4)2 + 4 HCl
H3PO4 + Fe = Fe3(PO4)2 + H2 =>
2 H3PO4 + 3 Fe = Fe3(PO4)2 + 3 H2
H2SO4 + Au = Au(SO4)3 + H2 =>
3 H2SO4 + Au = Au(SO4)3 + 3 H2
H2O + HNO3 = H2O2 + HNO2 =>
H2O + HNO3 = H2O2 + HNO2
SnCr2O7 + HCl = Sn + Cr + Cl + H2O =>
SnCr2O7 + 14 HCl = Sn + 2 Cr + 14 Cl + 7 H2O
Mn(NO3)2 + PbO2 + HNO3 = Pb(NO3)2 + HMnO4 + H2O =>
2 Mn(NO3)2 + 5 PbO2 + 6 HNO3 = 5 Pb(NO3)2 + 2 HMnO4 + 2 H2O
MgBr2 + Fl2 = MgFl2 + Br =>
MgBr2 + Fl2 = MgFl2 + 2 Br
HNO3 + NH3 = H2O + H2(NO)2 =>
HNO3 + NH3 = H2O + H2(NO)2
Cl2 + NaOH = NaCl + NaClO + H2O =>
Cl2 + 2 NaOH = NaCl + NaClO + H2O
HBr + Fe(OH)3 = H2O + Fe + Br =>
3 HBr + Fe(OH)3 = 3 H2O + Fe + 3 Br
Na2SO4 + BaCl2 + HNO3 = BaSO4 + HCl + NaNO3 =>
Na2SO4 + BaCl2 + 2 HNO3 = BaSO4 + 2 HCl + 2 NaNO3
KClO + HNO3 = KClO3 + NO2 + H2O =>
KClO + 4 HNO3 = KClO3 + 4 NO2 + 2 H2O
P4 + JO3{-} + OH{-} = PO4{3-} + J2 + H2O =>
P4 + 4 JO3{-} + 8 OH{-} = 4 PO4{3-} + 2 J2 + 4 H2O
[Cr(N2H4CO)6]4[Cr(CN)6]3 + KM12O4 + H2SO4 = K2Cr2O7 + M12SO4 + CO2 + KNO3 + K2SO4 + H2O =>
10[Cr(N2H4CO)6]4[Cr(CN)6]3 + 1176 KM12O4 + 1399 H2SO4 = 35 K2Cr2O7 + 1176 M12SO4 + 420 CO2 + 660 KNO3 + 223 K2SO4 + 1879 H2O
IBr3 + F2 = IF5 + Br2 =>
2 IBr3 + 5 F2 = 2 IF5 + 3 Br2
Cu(OH)2 + KCN = Cu(CN)2 + KOH =>
Cu(OH)2 + 2 KCN = Cu(CN)2 + 2 KOH
Ni2{+} + Zn = Ni + Zn2{+} =>
Ni2{+} + 2 Zn = 2 Ni + Zn2{+}
NaS + NiSO4 = NiS + NaSO4 =>
NaS + NiSO4 = NiS + NaSO4
MnO2 + NO2{-} + H2O = MnO4{-} + N2O + OH{-} =>
4 MnO2 + 6 NO2{-} + H2O = 4 MnO4{-} + 3 N2O + 2 OH{-}
C9H820 + O2 = CO2 + H2O =>
C9H820 + 214 O2 = 9 CO2 + 410 H2O
O5 + N2 = O2N =>
4 O5 + 5 N2 = 10 O2N
MoO3 + Zn + H2SO4 = Mo2O2O3 + ZnSO4 + H2O =>
2 MoO3 + Zn + H2SO4 = Mo2O2O3 + ZnSO4 + H2O
Ba(OH)2 + Na = Ba(OH)2Na =>
Ba(OH)2 + Na = Ba(OH)2Na
K2CrO7 + FeCl2 + HCl = CrCl3 + FeCl4 + KCl + H2O =>
2 K2CrO7 + 9 FeCl2 + 28 HCl = 2 CrCl3 + 9 FeCl4 + 4 KCl + 14 H2O
C4H9OH + O2 = C3H7COH + H2O =>
2 C4H9OH + O2 = 2 C3H7COH + 2 H2O
AlCl3 + (NH)F4 = AlF3 + (NH)Cl4 =>
4 AlCl3 + 3(NH)F4 = 4 AlF3 + 3(NH)Cl4
NaHCl + H2O = NaOH + Cl2 + H2 =>
2 NaHCl + 2 H2O = 2 NaOH + Cl2 + 2 H2
AlCl3 + (NH)F4 = AlF3 + (NH)Cl4 =>
4 AlCl3 + 3(NH)F4 = 4 AlF3 + 3(NH)Cl4
HBrO3 + HBr = H2O + Br2 =>
HBrO3 + 5 HBr = 3 H2O + 3 Br2
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| Équations équilibrées la veille | Équations équilibrées le lendemain |
Équations équilibrées sur12/31/23
Équations équilibrées sur01/30/23
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