Equations balanced on the previous day | Equations balanced on the next day |
NH4OH + HClO3 = NH4ClO3 + H2O
H3PO4 + H{+} = H3PO3{2e} + H2O =>
H3PO4 + 2 H{+} = H3PO3{2e} + H2O
H2CO3 + Mg = MgCO3 + H2 =>
H2CO3 + Mg = MgCO3 + H2
CuSO4 + Ca(OH)2 + H2O = CaSO4*2H2O + Cu(OH)2 =>
CuSO4 + Ca(OH)2 + 2 H2O = CaSO4*2H2O + Cu(OH)2
Na2 + CO3 + NH4OH = NaOH + (NH4)2CO3 =>
Na2 + CO3 + 2 NH4OH = 2 NaOH + (NH4)2CO3
MnCl2(aq) + (NH4)2S(aq) = MnS(s) + NH4Cl(aq) =>
MnCl2(aq) + (NH4)2S(aq) = MnS(s) + 2 NH4Cl(aq)
Al(NO3)3 + K2SO4 = Al2(SO4)3 + KNO3 =>
2 Al(NO3)3 + 3 K2SO4 = Al2(SO4)3 + 6 KNO3
KCl + H3Po4 = K3Po4 + HCl =>
3 KCl + H3Po4 = K3Po4 + 3 HCl
Mg(NO3)2 + NaNo3 = NaNO3 + Mg(No3)2 =>
Mg(NO3)2 + 2 NaNo3 = 2 NaNO3 + Mg(No3)2
NI + H2 = NIH2 =>
NI + H2 = NIH2
C5H8O2 + NaH + HCl = C5H12O2 + NaCl =>
C5H8O2 + 2 NaH + 2 HCl = C5H12O2 + 2 NaCl
CO + O2 = CO2 =>
2 CO + O2 = 2 CO2
Ca3(BO3)2 + H2O = Ca(OH)2 + H3BO3 =>
Ca3(BO3)2 + 6 H2O = 3 Ca(OH)2 + 2 H3BO3
FeCl3 + K4Fe(CN)6 = KCl + Fe4[Fe(CN)6]3 =>
4 FeCl3 + 3 K4Fe(CN)6 = 12 KCl + Fe4[Fe(CN)6]3
AsH3 + KIO3 + HCl = KH2AsO4 + KCl + I2 + H2O =>
5 AsH3 + 8 KIO3 + 3 HCl = 5 KH2AsO4 + 3 KCl + 4 I2 + 4 H2O
ZnSO4(aq) + NH3(aq) = Zn(NH3)2(aq) + SO4 =>
ZnSO4(aq) + 2 NH3(aq) = Zn(NH3)2(aq) + SO4
Pb(No3)2 + CoCl2 = PbCl2 + (No3)2Co =>
Pb(No3)2 + CoCl2 = PbCl2 + (No3)2Co
NH4 + Ag = AgN + H =>
NH4 + Ag = AgN + 4 H
C1H15S1 + O2 = CO2 + H2O + SO2 =>
4 C1H15S1 + 23 O2 = 4 CO2 + 30 H2O + 4 SO2
Co(NH3)6(NO3)3 + KOH = Co(NH3)5(OH)3 + KNO3 + H2O + NO =>
3 Co(NH3)6(NO3)3 + 4 KOH = 3 Co(NH3)5(OH)3 + 4 KNO3 + 2 H2O + 8 NO
KNO3 + Zn + H2SO4 = ZnSO4 + (NH4)2SO4 + K2SO4 + H2O =>
2 KNO3 + 8 Zn + 10 H2SO4 = 8 ZnSO4 + (NH4)2SO4 + K2SO4 + 6 H2O
C3H8O + O2 = CO2 + H2O =>
2 C3H8O + 9 O2 = 6 CO2 + 8 H2O
MgCO3 = MgO + CO2 =>
MgCO3 = MgO + CO2
NH4(OH) + HCl = (NH4)Cl + H2O =>
NH4(OH) + HCl = (NH4)Cl + H2O
C21H42O4 + H2O = C3H8O3 + C18H36O2 =>
C21H42O4 + H2O = C3H8O3 + C18H36O2
Ca + Bl2 = CaBl2 =>
Ca + Bl2 = CaBl2
KSCN + CuSO4 = CuSCN + KSO4 =>
KSCN + CuSO4 = CuSCN + KSO4
KCl + CuSO4 + H2O = K2Cu(SO4)2*6H2O + CuCl2 =>
2 KCl + 2 CuSO4 + 6 H2O = K2Cu(SO4)2*6H2O + CuCl2
Ba + FeCl2 = Fe + BaCl2 =>
Ba + FeCl2 = Fe + BaCl2
KHCO3 + C4H6O6 = K3C4H4O6 + H2O + CO2 =>
30 KHCO3 + 11 C4H6O6 = 10 K3C4H4O6 + 28 H2O + 34 CO2
SO4{2-} + CH3CHOO{-} + H{+} = HS{-} + CO2 + H2O =>
9 SO4{2-} + 8 CH3CHOO{-} + 17 H{+} = 9 HS{-} + 16 CO2 + 20 H2O
Na2B4O7 + H2SO4 + H2O = H3BO3 + Na2SO4 =>
Na2B4O7 + H2SO4 + 5 H2O = 4 H3BO3 + Na2SO4
Fe2O3 + HBr = H2O + Fe(Br)3 =>
Fe2O3 + 6 HBr = 3 H2O + 2 Fe(Br)3
KI + NaNO3 + H2SO4 = I2 + K2SO4 + NaNO2 + H2O =>
2 KI + NaNO3 + H2SO4 = I2 + K2SO4 + NaNO2 + H2O
H2S + Cu(NO3)2 = Cu2S2 + HNO3 =>
2 H2S + 2 Cu(NO3)2 = Cu2S2 + 4 HNO3
C2H5O2N + O2 = C2H2O3 + NH3 =>
2 C2H5O2N + O2 = 2 C2H2O3 + 2 NH3
Na2SO3 + CuCl2 = NaCl + CuSO3 =>
Na2SO3 + CuCl2 = 2 NaCl + CuSO3
KOH(aq) + CoCl(aq) = CoOH(aq) + KCl =>
KOH(aq) + CoCl(aq) = CoOH(aq) + KCl
C18H32O2 + CH4O = C19H36O2 + H2O =>
3 C18H32O2 + 22 CH4O = 4 C19H36O2 + 20 H2O
NaHCO3 + C6H8O7 = Na3C3H5O7 + CO2 + H2O =>
9 NaHCO3 + C6H8O7 = 3 Na3C3H5O7 + 6 CO2 + H2O
KCl + Pb(NO3)2 = PbCl2 + K(NO3) =>
2 KCl + Pb(NO3)2 = PbCl2 + 2 K(NO3)
NaOH(aq) + AgNO3(aq) = AgOH(aq) + NaNO3(aq) =>
NaOH(aq) + AgNO3(aq) = AgOH(aq) + NaNO3(aq)
FeCl4 + Fe = FeCl3 =>
3 FeCl4 + Fe = 4 FeCl3
OCN{-} + H{+} + H2O = H2CO3 + NH4{+} =>
OCN{-} + 2 H{+} + 2 H2O = H2CO3 + NH4{+}
CH2OH + K2Cr2O7 + H2SO4 = COOH + Cr2SO4 + K2SO4 + H2O =>
5 CH2OH + 2 K2Cr2O7 + 4 H2SO4 = 5 COOH + 2 Cr2SO4 + 2 K2SO4 + 9 H2O
C6H5COOH + NaHCO3 = C6H5COONa + H2O + CO3 =>
21 C6H5COOH + 22 NaHCO3 = 22 C6H5COONa + 19 H2O + 15 CO3
NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O
BaCl2(aq) + CK2O3(aq) = BaCO3(s) + ClK(aq) =>
BaCl2(aq) + CK2O3(aq) = BaCO3(s) + 2 ClK(aq)
Ca(No3)2 + K2SO4 = KNo3 + CaSO4 =>
Ca(No3)2 + K2SO4 = 2 KNo3 + CaSO4
N2 + LiH = Li3N + H2 =>
N2 + 6 LiH = 2 Li3N + 3 H2
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 02/01/24
Equations balanced on 03/02/23
-donnez-nous vos commentaires de votre expérience avec l'équilibreur d'équation chimique.