| Équations équilibrées la veille | Équations équilibrées le lendemain |
K2Cr2O7 + 3 C2H5OH + 8 HCl = 2 CrCl3 + 3 CH3CHO + 2 KCl + 7 H2O
S + O32 = SO3 =>
32 S + 3 O32 = 32 SO3
C2H5OH + K = C2H5OK + H2 =>
2 C2H5OH + 2 K = 2 C2H5OK + H2
(NH4)2S(aq) + Pb(NO3)2(aq) = PbS(s) + NH4NO3(aq) =>
(NH4)2S(aq) + Pb(NO3)2(aq) = PbS(s) + 2 NH4NO3(aq)
K2Cr2O7 + C2H5OH + HCl = CrCl3 + CH3CHO + KCl + H2O =>
K2Cr2O7 + 3 C2H5OH + 8 HCl = 2 CrCl3 + 3 CH3CHO + 2 KCl + 7 H2O
NiCl2 + K4FeCN6 = NiCN6 + K4FeCl2 =>
NiCl2 + K4FeCN6 = NiCN6 + K4FeCl2
MnO4{-}(aq) + H{+}(aq) + e = Mn2{+}(aq) + H2O(l) =>
2 MnO4{-}(aq) + 16 H{+}(aq) + 13e = Mn2{+}(aq) + 8 H2O(l)
Ag(s) + HCI(aq) = AgCI(s) + H2(g) =>
2 Ag(s) + 2 HCI(aq) = 2 AgCI(s) + H2(g)
C2H5OH + K2Cr2O7 + HCl = CH3COOH + CrCl3 + KCl + H2O =>
3 C2H5OH + 2 K2Cr2O7 + 16 HCl = 3 CH3COOH + 4 CrCl3 + 4 KCl + 11 H2O
NaCl + Ca(NO3)2 = Na(NO3)2 + CaCl =>
NaCl + Ca(NO3)2 = Na(NO3)2 + CaCl
CH3COOK + H2O = CH2COOK + H3O =>
CH3COOK + H2O = CH2COOK + H3O
Mg + BaNO3 = Mg(NO3)2 + Ba =>
Mg + 2 BaNO3 = Mg(NO3)2 + 2 Ba
C2H5OH + K2Cr2O7 + HCl = CH3COOH + CrCl3 + KCl + H2O =>
3 C2H5OH + 2 K2Cr2O7 + 16 HCl = 3 CH3COOH + 4 CrCl3 + 4 KCl + 11 H2O
HCl + Na2O = H2O + NaCl =>
2 HCl + Na2O = H2O + 2 NaCl
Fe + HNO3 = Fe(NO3)2 + NH4NH3 + H2O =>
17 Fe + 38 HNO3 = 17 Fe(NO3)2 + 2 NH4NH3 + 12 H2O
C6H5COOH + CuO = C6H5OH + Cu + CO2 =>
C6H5COOH + CuO = C6H5OH + Cu + CO2
BeCl2 = Be + Cl =>
BeCl2 = Be + 2 Cl
C2H5OH + K2Cr2O7 + HCl = CH3COOH + CrCl3 + KCl + H2O =>
3 C2H5OH + 2 K2Cr2O7 + 16 HCl = 3 CH3COOH + 4 CrCl3 + 4 KCl + 11 H2O
NH3 + AlNO3 + H2O = Al(OH)3 + NH4NO3 =>
2 NH3 + 4 AlNO3 + 9 H2O = 4 Al(OH)3 + 3 NH4NO3
Fe(NO3)2 + K2SO3 = FeSO3 + KNO3 =>
Fe(NO3)2 + K2SO3 = FeSO3 + 2 KNO3
C2H5OH + K2Cr2O7 + HCl = CH3COOH + CrCl3 + KCl + H2O =>
3 C2H5OH + 2 K2Cr2O7 + 16 HCl = 3 CH3COOH + 4 CrCl3 + 4 KCl + 11 H2O
CaCo3 + NaCl = CaCl2 + Na2Co3 =>
CaCo3 + 2 NaCl = CaCl2 + Na2Co3
C2H5OH + K2Cr2O7 + HCl = CH3COOH + CrCl3 + KCl + H2O =>
3 C2H5OH + 2 K2Cr2O7 + 16 HCl = 3 CH3COOH + 4 CrCl3 + 4 KCl + 11 H2O
Fe(SCN)3NaF = Na(SCN)3FeF =>
Fe(SCN)3NaF = Na(SCN)3FeF
CaCo3 + NaCl = CaCl2 + Na2Co3 =>
CaCo3 + 2 NaCl = CaCl2 + Na2Co3
SiCl5 = Si + Cl2 =>
2 SiCl5 = 2 Si + 5 Cl2
C2H5OH + K2Cr2O7 + HCl = CH3COOH + CrCl3 + KCl + H2O =>
3 C2H5OH + 2 K2Cr2O7 + 16 HCl = 3 CH3COOH + 4 CrCl3 + 4 KCl + 11 H2O
MgNH4OH = MgOHNH4 =>
MgNH4OH = MgOHNH4
S + O2 = SO3 =>
2 S + 3 O2 = 2 SO3
CaCo3 + NaCl = CaCl2 + Na2Co3 =>
CaCo3 + 2 NaCl = CaCl2 + Na2Co3
C2H5OH + K2Cr2O7 + HCl = CH3COOH + CrCl3 + KCl + H2O =>
3 C2H5OH + 2 K2Cr2O7 + 16 HCl = 3 CH3COOH + 4 CrCl3 + 4 KCl + 11 H2O
CaCo3 + NaCl = CaCl2 + Na2Co3 =>
CaCo3 + 2 NaCl = CaCl2 + Na2Co3
K2Cr2O7 + HCl + C2H5OH = CrCl3 + CO2 + KCl + H2O =>
2 K2Cr2O7 + 16 HCl + C2H5OH = 4 CrCl3 + 2 CO2 + 4 KCl + 11 H2O
Pb + Na2S = PbS + Na =>
Pb + Na2S = PbS + 2 Na
C2H5OH + K2Cr2O7 + HCl = CH3COOH + CrCl3 + KCl + H2O =>
3 C2H5OH + 2 K2Cr2O7 + 16 HCl = 3 CH3COOH + 4 CrCl3 + 4 KCl + 11 H2O
H2SO4 + K4Fe(CN)6 + KMnO4 = K3Fe(CN)6 + MnSO4 + K2SO4 + H2O =>
4 H2SO4 + 5 K4Fe(CN)6 + KMnO4 = 5 K3Fe(CN)6 + MnSO4 + 3 K2SO4 + 4 H2O
Na + H2SO4 = H2 + NaHSO4 =>
2 Na + 2 H2SO4 = H2 + 2 NaHSO4
BaO + HNO3 = Ba(NO3)2 + H2O =>
BaO + 2 HNO3 = Ba(NO3)2 + H2O
K2Cr2O7 + C2H5OH + HCl = CrCl3 + CH3CHO + KCl + H2O =>
K2Cr2O7 + 3 C2H5OH + 8 HCl = 2 CrCl3 + 3 CH3CHO + 2 KCl + 7 H2O
O{2+} + H{-} = H2O =>
O{2+} + 2 H{-} = H2O
NaCl + H2SO4 = Na2SO4 + HCl =>
2 NaCl + H2SO4 = Na2SO4 + 2 HCl
NO + S + OH{-} = NO3{-} + S{2-} + H2O =>
2 NO + 3 S + 8 OH{-} = 2 NO3{-} + 3 S{2-} + 4 H2O
MgSO4 + H2SO4 = MgH + SO4 =>
2 MgSO4 + H2SO4 = 2 MgH + 3 SO4
Na2CO3 + HNO3 = NaNO3 + CO2 + H2O =>
Na2CO3 + 2 HNO3 = 2 NaNO3 + CO2 + H2O
CuNaCl2HO = CuCl2NaHO =>
CuNaCl2HO = CuCl2NaHO
Hg + O2 = HgO =>
2 Hg + O2 = 2 HgO
CaCo3 + NaCl = CaCl2 + Na2Co3 =>
CaCo3 + 2 NaCl = CaCl2 + Na2Co3
Na2SiO3H2SO4 = H2SiO3Na2SO4 =>
Na2SiO3H2SO4 = H2SiO3Na2SO4
HO{-} + Fe{3+} = Fe(OH)3 =>
3 HO{-} + Fe{3+} = Fe(OH)3
Cr(s) + HCl(aq) = CrCl2(aq) + H2(g) =>
Cr(s) + 2 HCl(aq) = CrCl2(aq) + H2(g)
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| Équations équilibrées la veille | Équations équilibrées le lendemain |
Équations équilibrées sur09/10/24
Équations équilibrées sur10/10/23
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