Équations équilibrées la veille |
2 Na + 2 HCl = 2 NaCl + H2*
Br2 + CuI2 = CuBr2 + I2 =>
Br2 + CuI2 = CuBr2 + I2
Sr(NO3)2 + NaCl = SrCl2 + NaNO3 =>
Sr(NO3)2 + 2 NaCl = SrCl2 + 2 NaNO3
Li + HCl2 = LiCl + H =>
2 Li + HCl2 = 2 LiCl + H
NaAl(OH)4 + KBr = NaBr + KAl(OH)4 =>
NaAl(OH)4 + KBr = NaBr + KAl(OH)4
(NH4)2SO4 + NaCl = (NH4)Cl + Na2SO4 =>
(NH4)2SO4 + 2 NaCl = 2(NH4)Cl + Na2SO4
Al2(O)3 + HCl = Al(Cl)3 + H2O =>
Al2(O)3 + 6 HCl = 2 Al(Cl)3 + 3 H2O
CuCl2 + NaOH = Cu(OH)2 + NaCl =>
CuCl2 + 2 NaOH = Cu(OH)2 + 2 NaCl
CUSO4 + BaC12 = BaSO4 + CUC12 =>
CUSO4 + BaC12 = BaSO4 + CUC12
Al + NaOH + H2O = H2 + Al(OH)4{-} + Na{+} =>
2 Al + 2 NaOH + 6 H2O = 3 H2 + 2 Al(OH)4{-} + 2 Na{+}
CF4 + Br2 = CBr4 + F2 =>
CF4 + 2 Br2 = CBr4 + 2 F2
MgCl2 + HNO3 = Mg(NO3)2 + HCl =>
MgCl2 + 2 HNO3 = Mg(NO3)2 + 2 HCl
NiCO3 = NiOCO2 =>
NiCO3 = NiOCO2
CO2 + H2O = C7H16 + O =>
7 CO2 + 8 H2O = C7H16 + 22 O
CS2 + Cl2 = CCl4 + S2Cl2 =>
CS2 + 3 Cl2 = CCl4 + S2Cl2
ZnS + CH3COONa + H2O = CH3COOH + Na2[Zn(OH)4] + Na2S =>
ZnS + 4 CH3COONa + 4 H2O = 4 CH3COOH + Na2[Zn(OH)4] + Na2S
CuCO3 + Fe(OH)3 = Cu(OH)2 + Fe2(CO3)3 =>
3 CuCO3 + 2 Fe(OH)3 = 3 Cu(OH)2 + Fe2(CO3)3
Al2(O)3 + HCl = Al(Cl)3 + H2O =>
Al2(O)3 + 6 HCl = 2 Al(Cl)3 + 3 H2O
H2 + Ga2(SO4)3 = H2SO4 + Ga =>
3 H2 + Ga2(SO4)3 = 3 H2SO4 + 2 Ga
Au2(SO4)3 = Au2O3 + SO3 =>
Au2(SO4)3 = Au2O3 + 3 SO3
C6H12O2 + NaHCO3 = H2O + CO2 + Na =>
C6H12O2 + 32 NaHCO3 = 22 H2O + 38 CO2 + 32 Na
BaOH2 + NH3PO4 = NH3 + Ba3(PO4)2 + H2O =>
3 BaOH2 + 2 NH3PO4 = 2 NH3 + Ba3(PO4)2 + 3 H2O
Al2(O)3 + HCl = Al(Cl)3 + H2O =>
Al2(O)3 + 6 HCl = 2 Al(Cl)3 + 3 H2O
K2Cr2O7 + H2SO4 + C4H9OH = Cr2(SO4)3 + K2SO4 + C3H7COH + H2O =>
K2Cr2O7 + 4 H2SO4 + 3 C4H9OH = Cr2(SO4)3 + K2SO4 + 3 C3H7COH + 7 H2O
K2CO3 + AgNO2 = K2NO2 + AgCO3 =>
K2CO3 + AgNO2 = K2NO2 + AgCO3
K2Cr2O7 + H2SO4 + C4H9OH = Cr2(SO4)3 + K2SO4 + C3H7COOH + H2O =>
2 K2Cr2O7 + 8 H2SO4 + 3 C4H9OH = 2 Cr2(SO4)3 + 2 K2SO4 + 3 C3H7COOH + 11 H2O
K2Cr2O7 + H2SO4 + C4H9OH = Cr2(SO4)3 + K2SO4 + CH3CH2CH2COOH + H2O =>
2 K2Cr2O7 + 8 H2SO4 + 3 C4H9OH = 2 Cr2(SO4)3 + 2 K2SO4 + 3 CH3CH2CH2COOH + 11 H2O
K2Cr2O7 + H2SO4 + C4H9OH = Cr2(SO4)3 + K2SO4 + CH3COOH + H2O =>
4 K2Cr2O7 + 16 H2SO4 + 3 C4H9OH = 4 Cr2(SO4)3 + 4 K2SO4 + 6 CH3COOH + 19 H2O
BaS + Sn(NO3)4 = Ba(NO3)2 + SnS2 =>
2 BaS + Sn(NO3)4 = 2 Ba(NO3)2 + SnS2
K2CrO4(aq) + HCl(aq) = Cl2 + CrCl3 + KCl + H2O =>
2 K2CrO4(aq) + 16 HCl(aq) = 3 Cl2 + 2 CrCl3 + 4 KCl + 8 H2O
Fe(OH)3 + Al = Fe + Al(OH)3 =>
Fe(OH)3 + Al = Fe + Al(OH)3
K2CrO4(aq) + HCl(aq) = H2CrO4 + KCl =>
K2CrO4(aq) + 2 HCl(aq) = H2CrO4 + 2 KCl
C2H2 + Na = C2HNa + H2 =>
2 C2H2 + 2 Na = 2 C2HNa + H2
K2CrO4(aq) + HCl(aq) = K2Cr2O7(aq) + KCl(aq) + H2O(l) =>
2 K2CrO4(aq) + 2 HCl(aq) = K2Cr2O7(aq) + 2 KCl(aq) + H2O(l)
K2CrO4(aq) + HCl(aq) = K2Cr2O7 + KCl + H2O =>
2 K2CrO4(aq) + 2 HCl(aq) = K2Cr2O7 + 2 KCl + H2O
K2CrO4 + HBr = CrBr3 + Br2 + H2O + KBr =>
2 K2CrO4 + 16 HBr = 2 CrBr3 + 3 Br2 + 8 H2O + 4 KBr
K2S(aq) + HI(aq) = H2S(g) + KI(aq) =>
K2S(aq) + 2 HI(aq) = H2S(g) + 2 KI(aq)
K2S(aq) + HI(aq) = K2I + HS =>
K2S(aq) + HI(aq) = K2I + HS
NO2 = O2 + N2 =>
2 NO2 = 2 O2 + N2
C5H4O2 + CH5N3O = C6H7N3O2 + H2O =>
C5H4O2 + CH5N3O = C6H7N3O2 + H2O
FeO2 = Fe + O2 =>
FeO2 = Fe + O2
K2S2O8 + NaI = I2 + K2SO4 + Na2SO4 =>
K2S2O8 + 2 NaI = I2 + K2SO4 + Na2SO4
K2S2O8 + NaI = K2I + NaS2O8 =>
K2S2O8 + NaI = K2I + NaS2O8
K2SO4 + Ba(CH3COO)2 = BaSO4 + CH3COOK =>
K2SO4 + Ba(CH3COO)2 = BaSO4 + 2 CH3COOK
C + S8 = CS2 =>
4 C + S8 = 4 CS2
K3[Cr(OH)6] + H2SO4 = Cr(OH)3 + K2SO4 + H2O =>
2 K3[Cr(OH)6] + 3 H2SO4 = 2 Cr(OH)3 + 3 K2SO4 + 6 H2O
KBr + HClO4 = KClO4 + HBr =>
KBr + HClO4 = KClO4 + HBr
KClO3(g) = KCl(g) + O2 =>
2 KClO3(g) = 2 KCl(g) + 3 O2
KIO3(aq) + KI(aq) + H2SO4(aq) = K2SO4(aq) + H2O(l) + I2(aq) =>
KIO3(aq) + 5 KI(aq) + 3 H2SO4(aq) = 3 K2SO4(aq) + 3 H2O(l) + 3 I2(aq)
KIO3 + FeSO4 + H2SO4 = Fe2(SO4)3 + I + K2SO4 + H2O =>
2 KIO3 + 10 FeSO4 + 6 H2SO4 = 5 Fe2(SO4)3 + 2 I + K2SO4 + 6 H2O
Équilibrer l'équation de toute réaction chimique
Équations équilibrées la veille |
Équations équilibrées sur10/18/24
Équations équilibrées sur11/17/23
-donnez-nous vos commentaires de votre expérience avec l'équilibreur d'équation chimique.