Équations équilibrées la veille | Équations équilibrées le lendemain |
2 NaHSO3 + Ba(OH)2 = BaSO3 + Na2SO3 + 2 H2O
CaCO3 + SO2 + H2O = CaSO4 + CO2 + H2 =>
CaCO3 + SO2 + H2O = CaSO4 + CO2 + H2
AgCl + KOH = KCl + Ag + O2 + H2O =>
4 AgCl + 4 KOH = 4 KCl + 4 Ag + O2 + 2 H2O
Pb(NO3)2 + HCl = PbCl2 + HNO3 =>
Pb(NO3)2 + 2 HCl = PbCl2 + 2 HNO3
Ce(IO3)4 = Ce{4+} + IO3{-} =>
Ce(IO3)4 = Ce{4+} + 4 IO3{-}
(NH4)2SO4 + NaOH = NH4OH + Na2SO4 =>
(NH4)2SO4 + 2 NaOH = 2 NH4OH + Na2SO4
AgI + F2 = AgF + I2 =>
2 AgI + F2 = 2 AgF + I2
Fe + KSCN + H2O2 = FeO2 + KSCNH2 =>
Fe + KSCN + H2O2 = FeO2 + KSCNH2
CaCO3 + HCl(aq) = CaCl2 + H2CO3 =>
CaCO3 + 2 HCl(aq) = CaCl2 + H2CO3
C2H4O + Cu(OH)2 = C2H4O2 + Cu2O + H2O =>
C2H4O + 2 Cu(OH)2 = C2H4O2 + Cu2O + 2 H2O
NaHCO3(aq) + CH3COOH(aq) = NaCH3COO(aq) + H2O(l) + CO2(g) =>
NaHCO3(aq) + CH3COOH(aq) = NaCH3COO(aq) + H2O(l) + CO2(g)
CaCl2 + Ca(OH)2 = Ca(OH)Cl =>
CaCl2 + Ca(OH)2 = 2 Ca(OH)Cl
NaHCO3 + HCl(aq) = NaCl(aq) + H2O + CO2 =>
NaHCO3 + HCl(aq) = NaCl(aq) + H2O + CO2
Sn + Zn(NO3)2 = Sn(NO3) + Zn =>
2 Sn + Zn(NO3)2 = 2 Sn(NO3) + Zn
NO2 + H2SO4 = HNO3 + SO2 =>
2 NO2 + H2SO4 = 2 HNO3 + SO2
CH4O + Cr2O7{2-} + H{+} = CH2O + Cr{3+} + H2O =>
3 CH4O + Cr2O7{2-} + 8 H{+} = 3 CH2O + 2 Cr{3+} + 7 H2O
C6H12 = C5H9CH3 =>
C6H12 = C5H9CH3
Fe2O3 + NaCl = FeCl3 + Na2O =>
Fe2O3 + 6 NaCl = 2 FeCl3 + 3 Na2O
Li2SO4 + Ca(OH)2 = CaSO4 + LiOH =>
Li2SO4 + Ca(OH)2 = CaSO4 + 2 LiOH
C3H8O2 + KMnO4 = C3H2O4K2 + MnO2 + KOH + H2O =>
3 C3H8O2 + 8 KMnO4 = 3 C3H2O4K2 + 8 MnO2 + 2 KOH + 8 H2O
Al + KOH + H2O = KAl(OH)4 + H2 =>
2 Al + 2 KOH + 6 H2O = 2 KAl(OH)4 + 3 H2
Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3
Br2 + CoI3 = I2 + CoBr3 =>
3 Br2 + 2 CoI3 = 3 I2 + 2 CoBr3
Na2O + HBr = NaBr + H2O =>
Na2O + 2 HBr = 2 NaBr + H2O
HF + H2O = F{-} + H3O{+} =>
HF + H2O = F{-} + H3O{+}
Cu2S + H2SO4 = CuSO4 + S + H2O =>
3 Cu2S + 8 H2SO4 = 6 CuSO4 + 5 S + 8 H2O
NaHCO3(s) + HCl = NaCl + H2O + CO2 =>
NaHCO3(s) + HCl = NaCl + H2O + CO2
Al + NO2 = Al2O3 + NO =>
2 Al + 3 NO2 = Al2O3 + 3 NO
CuCl2 + H2O = CuOHCl + HCl =>
CuCl2 + H2O = CuOHCl + HCl
AgCl + HCl = H[AgCl2] =>
AgCl + HCl = H[AgCl2]
KCl + H2O2 = KOH + HCl + O2 =>
2 KCl + 2 H2O2 = 2 KOH + 2 HCl + O2
BaCl2 + K2SO4 = BaSO4 + KCl =>
BaCl2 + K2SO4 = BaSO4 + 2 KCl
KNO3 + S8 = K2SO4 + SO2 + N2 =>
8 KNO3 + S8 = 4 K2SO4 + 4 SO2 + 4 N2
Br2 + Cl2 = Br3Cl =>
3 Br2 + Cl2 = 2 Br3Cl
K3P + O2 = K3PO4 =>
K3P + 2 O2 = K3PO4
Cu{+} + IO2{-} = Cu{2+} + I2 + O{2-} =>
6 Cu{+} + 2 IO2{-} = 6 Cu{2+} + I2 + 4 O{2-}
AlI3 + SrS = AlS + SrI3 =>
AlI3 + SrS = AlS + SrI3
Rb + HNO3 = RbNO3 + H2O + NH3 =>
8 Rb + 9 HNO3 = 8 RbNO3 + 3 H2O + NH3
Ca(ClO)2 + Na3PO4 = Ca3(PO4)2 + NaClO =>
3 Ca(ClO)2 + 2 Na3PO4 = Ca3(PO4)2 + 6 NaClO
C6H5CH(OH)CH3 + K2Cr2O7 + H2SO4 = Cr2(SO4)3 + K2SO4 + C6H5COCH3 + H2O =>
3 C6H5CH(OH)CH3 + K2Cr2O7 + 4 H2SO4 = Cr2(SO4)3 + K2SO4 + 3 C6H5COCH3 + 7 H2O
C2H5Br + Br2 = C2H4Br + HBr =>
2 C2H5Br + Br2 = 2 C2H4Br + 2 HBr
Mg(s) + Cu(NO3)2 = Mg(NO3)2 + Cu =>
Mg(s) + Cu(NO3)2 = Mg(NO3)2 + Cu
C14H10O2 + NaBH4 + H2O = C14H1402 + NaOH + H3BO3 =>
2 C14H10O2 + 349 NaBH4 + 1392 H2O = 2 C14H1402 + 349 NaOH + 349 H3BO3
U + O = UO3 =>
U + 3 O = UO3
C20H42(s) + O2(g) = CO2 + H2O =>
2 C20H42(s) + 61 O2(g) = 40 CO2 + 42 H2O
KHSO4 + NaHCO3 = K2SO4 + Na2SO4 + CO2 + H2O =>
2 KHSO4 + 2 NaHCO3 = K2SO4 + Na2SO4 + 2 CO2 + 2 H2O
Li + Cu(SO4) = Li2(SO4) + Cu =>
2 Li + Cu(SO4) = Li2(SO4) + Cu
Cu(OH)2 + NH4OH = (Cu(NH3)4)(OH)2 + H2O =>
Cu(OH)2 + 4 NH4OH = (Cu(NH3)4)(OH)2 + 4 H2O
FeCl3 + HNo3 = Fe(No3)3 + HCl =>
FeCl3 + 3 HNo3 = Fe(No3)3 + 3 HCl
Pb{2+} + OH{-} = Pb(OH)2 =>
Pb{2+} + 2 OH{-} = Pb(OH)2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 |
Équations équilibrées la veille | Équations équilibrées le lendemain |
Équations équilibrées sur10/22/24
Équations équilibrées sur11/21/23
-donnez-nous vos commentaires de votre expérience avec l'équilibreur d'équation chimique.