| Équations équilibrées la veille | Équations équilibrées le lendemain |
2 AlBr3 + 3 Cl2 = 2 Al + 3 Br2Cl2
Zn(NO3)2 + Ba(OH)2 = Zn(OH)2 + Ba(NO3)2 =>
Zn(NO3)2 + Ba(OH)2 = Zn(OH)2 + Ba(NO3)2
HBr + Ba(OH)2 = BaBr2 + H2O =>
2 HBr + Ba(OH)2 = BaBr2 + 2 H2O
C3H6(g) + O2(g) = CO2(g) + H2O(g) =>
2 C3H6(g) + 9 O2(g) = 6 CO2(g) + 6 H2O(g)
AsCl5 = As + Cl5 =>
AsCl5 = As + Cl5
Ca(OH)2 + CO2 = Ca(HCO3)2 =>
Ca(OH)2 + 2 CO2 = Ca(HCO3)2
Na2B4O7*10H2O + Cr2(SO4)3 = Cr(BO2)3 + SO3 + NaBO2 + H2O =>
3 Na2B4O7*10H2O + Cr2(SO4)3 = 2 Cr(BO2)3 + 3 SO3 + 6 NaBO2 + 30 H2O
CH3OH + NaClO3 + H2SO4 = ClO2 + Na2SO4*NaHSO4 + H2O + CO2 =>
CH3OH + 6 NaClO3 + 4 H2SO4 = 6 ClO2 + 2 Na2SO4*NaHSO4 + 5 H2O + CO2
KClO3 = KCl + O2 =>
2 KClO3 = 2 KCl + 3 O2
Zn(s) + HNO3(aq) = Zn(NO3)2(aq) + NO(g) + H2O(aq) =>
3 Zn(s) + 8 HNO3(aq) = 3 Zn(NO3)2(aq) + 2 NO(g) + 4 H2O(aq)
I2 + I{-} = I3{-} =>
I2 + I{-} = I3{-}
C3HN + CN4O8 = CO2 + N2 + H2O =>
12 C3HN + 13 CN4O8 = 49 CO2 + 32 N2 + 6 H2O
FeSO4 + Al = AlSO4 + Fe =>
FeSO4 + Al = AlSO4 + Fe
BaCl2 + K2Cr2O7 = BaCr2O7 + KCl =>
BaCl2 + K2Cr2O7 = BaCr2O7 + 2 KCl
C5H12(i) + O2(g) = CO2(g) + H2O(g) =>
C5H12(i) + 8 O2(g) = 5 CO2(g) + 6 H2O(g)
C6H8O6 + CaCO3 = Ca(C6H7O6)2 + H2O + CO2 =>
2 C6H8O6 + CaCO3 = Ca(C6H7O6)2 + H2O + CO2
SnBr2 + K3PO4 = Sn3(PO4)2 + KBr =>
3 SnBr2 + 2 K3PO4 = Sn3(PO4)2 + 6 KBr
C57H114O6 + O2 = CO2 + H2O =>
2 C57H114O6 + 165 O2 = 114 CO2 + 114 H2O
(b)Sc2O3(s) + H2O(l) = Sc(OH)3(s) =>
(b)Sc2O3(s) + 3 H2O(l) = 2 Sc(OH)3(s)
K4[Fe(CN6)] + KMnO4 + H2SO4 = Fe2(SO4)3 + CO2 + HNO3 + MnSO4 + K2SO4 + H2O =>
10 K4[Fe(CN6)] + 82 KMnO4 + 158 H2SO4 = 5 Fe2(SO4)3 + 10 CO2 + 60 HNO3 + 82 MnSO4 + 61 K2SO4 + 128 H2O
NaClO + NaBr + H2SO4 = Br2 + Na2SO4 + NaCl + H2O =>
NaClO + 2 NaBr + H2SO4 = Br2 + Na2SO4 + NaCl + H2O
Mn2{+} + Br2 + OH{-} = MnO4{-} + Br{-} + H2O =>
2 Mn2{+} + 13 Br2 + 32 OH{-} = 4 MnO4{-} + 26 Br{-} + 16 H2O
Fe(NH4)2(SO4)2 + NaOH = Fe(NH4)2(OH)2 + NaSO4 =>
Fe(NH4)2(SO4)2 + 2 NaOH = Fe(NH4)2(OH)2 + 2 NaSO4
Ca + Cl2 + Li2O = CaO + LiCl =>
Ca + Cl2 + Li2O = CaO + 2 LiCl
HC4H7O3 + H2O = H3O + C4H7O3 =>
HC4H7O3 + H2O = H3O + C4H7O3
N2O5 + H2O = HNO3 =>
N2O5 + H2O = 2 HNO3
Na2B4O7 + CoSO4 = NaBO2 + Co(BO2)3 + SO2 + O2 =>
6 Na2B4O7 + 4 CoSO4 = 12 NaBO2 + 4 Co(BO2)3 + 4 SO2 + O2
C4H8O + O2 = CO2 + H2O =>
2 C4H8O + 11 O2 = 8 CO2 + 8 H2O
Ca(OH)2 + KNo3 = KOH + Ca(No3)2 =>
Ca(OH)2 + 2 KNo3 = 2 KOH + Ca(No3)2
K2CO3 + H2SO4 = K2SO4 + H2O + CO2 =>
K2CO3 + H2SO4 = K2SO4 + H2O + CO2
Na3[Cr(OH)6] + NaOH + PbO2 = Na2CrO4 + H2O + Na2[Pb(OH)4] =>
2 Na3[Cr(OH)6] + 4 NaOH + 3 PbO2 = 2 Na2CrO4 + 2 H2O + 3 Na2[Pb(OH)4]
CO2 + H2O = H2CO3 =>
CO2 + H2O = H2CO3
Mn(N03)2 + NaBiO3 + HNO3 = NaMnO4 + Bi(NO3)3 + NaNO3 + H2O =>
2 Mn(N03)2 + 37 NaBiO3 + 134 HNO3 = 2 NaMnO4 + 37 Bi(NO3)3 + 35 NaNO3 + 67 H2O
K2SO4 + BaCe2 = KCe + BaSO4 =>
K2SO4 + BaCe2 = 2 KCe + BaSO4
H2SO4 + Cu(OH)2 = CuSO4 + H2O =>
H2SO4 + Cu(OH)2 = CuSO4 + 2 H2O
Ca + O2 = CaO =>
2 Ca + O2 = 2 CaO
CH3CH2COOH + NaOH = C2H6 + NaCO3 + H2O =>
16 CH3CH2COOH + 14 NaOH = 17 C2H6 + 14 NaCO3 + 4 H2O
NH7C3O2(s) + O2(g) = CO2(g) + H2O(l) + N2(g) =>
4 NH7C3O2(s) + 15 O2(g) = 12 CO2(g) + 14 H2O(l) + 2 N2(g)
Pb + Ca(NO3)2 = Ca + Pb(NO3)2 =>
Pb + Ca(NO3)2 = Ca + Pb(NO3)2
S20 + H2 = SH2 =>
S20 + 20 H2 = 20 SH2
CrCl3*6H2O + C5H8O2 + CH4N2O = Cr(acac)3 + NH4Cl + CO2 + H2O =>
24 CrCl3*6H2O + 3 C5H8O2 + 36 CH4N2O = 8 Cr(acac)3 + 72 NH4Cl + 51 CO2 + 84 H2O
Mg + O2 = MgO =>
2 Mg + O2 = 2 MgO
NaAlCO3 = AlNaCO3 =>
NaAlCO3 = AlNaCO3
Al + HgO = Al2O3 + Hg =>
2 Al + 3 HgO = Al2O3 + 3 Hg
NaOCl + Hg = NaCl + HgO =>
NaOCl + Hg = NaCl + HgO
KCrO2 + NaOH = NaCrO2 + KOH =>
KCrO2 + NaOH = NaCrO2 + KOH
NaAlCO3 = AlNaCO3 =>
NaAlCO3 = AlNaCO3
CuSO4 + Na2CO3 + H2O = (CuOH)2CO3 + Na2SO4 + Cu(HCO3)2 =>
3 CuSO4 + 3 Na2CO3 + 2 H2O = (CuOH)2CO3 + 3 Na2SO4 + Cu(HCO3)2
K2Cr2O7 + HNO3 + Na2S = Na2SO4 + KNO3 + Cr(NO3)3 + H2O =>
4 K2Cr2O7 + 32 HNO3 + 3 Na2S = 3 Na2SO4 + 8 KNO3 + 8 Cr(NO3)3 + 16 H2O
H2SO4 + (CuOH)2CO3 = CuSO4 + H2O + H2CO3 =>
2 H2SO4 + (CuOH)2CO3 = 2 CuSO4 + 2 H2O + H2CO3
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| Équations équilibrées la veille | Équations équilibrées le lendemain |
Équations équilibrées sur11/03/24
Équations équilibrées sur12/03/23
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