Équations équilibrées la veille |
C6H14 + HBr = C6H15Br
(NaOH) + CO2 = NaHCO3 =>
(NaOH) + CO2 = NaHCO3
Cr2O3 + CH3COOH = Cr(CH3COO)3 + H2O =>
Cr2O3 + 6 CH3COOH = 2 Cr(CH3COO)3 + 3 H2O
FeCl3 + Na2CO3 + H2O = Fe(OH)3 + CO2 + NaCl =>
2 FeCl3 + 3 Na2CO3 + 3 H2O = 2 Fe(OH)3 + 3 CO2 + 6 NaCl
KBrO3 + HCl = KBr + H2O + Cl2 =>
KBrO3 + 6 HCl = KBr + 3 H2O + 3 Cl2
KCN + NiCl2 = Ni(CN)2 + KCl =>
2 KCN + NiCl2 = Ni(CN)2 + 2 KCl
LiOH + FeN3O9 = LiNO3 + FeO3H3 =>
3 LiOH + FeN3O9 = 3 LiNO3 + FeO3H3
HOC(CH2CO2H)2 + NaHCO3 = Na3C6H5O7 + H2O + CO2 =>
18 HOC(CH2CO2H)2 + 51 NaHCO3 = 17 Na3C6H5O7 + 46 H2O + 39 CO2
C4H9OH + CO2 = C4H8O2 + CH4 =>
2 C4H9OH + CO2 = 2 C4H8O2 + CH4
MgSO3 = Mg(s) + S8(s) + O2(g) =>
8 MgSO3 = 8 Mg(s) + S8(s) + 12 O2(g)
NH4CH3COO + H2O = NH4OH + HCH3COO =>
NH4CH3COO + H2O = NH4OH + HCH3COO
H2NbF7 + NaOH = NaNbO3 + NaF + H2O =>
H2NbF7 + 8 NaOH = NaNbO3 + 7 NaF + 5 H2O
Ca3[PO4]2 + H2SO4 = H3PO4 + CaSO4 =>
Ca3[PO4]2 + 3 H2SO4 = 2 H3PO4 + 3 CaSO4
C4H9MgBr + C4H8O + H2O = C8H18O + HOMgBr =>
C4H9MgBr + C4H8O + H2O = C8H18O + HOMgBr
CuS + NO3{-} + H{+} = CuSO4 + NO2 + H2O =>
CuS + 8 NO3{-} + 8 H{+} = CuSO4 + 8 NO2 + 4 H2O
K + H3PO4(aq) = H2 + K3PO4 =>
6 K + 2 H3PO4(aq) = 3 H2 + 2 K3PO4
C240H90N4S2 + O2 = CO2 + H2O + N2 + SO2 =>
2 C240H90N4S2 + 529 O2 = 480 CO2 + 90 H2O + 4 N2 + 4 SO2
CuCl2 + KCN = CuCN + C2N2 + KCl =>
2 CuCl2 + 4 KCN = 2 CuCN + C2N2 + 4 KCl
CoF2 = F2Co =>
CoF2 = F2Co
[Co(H2O)6]{3+} + H2O = [Co(H2O)6]{2+} + O2 + H{+) =>
4[Co(H2O)6]{3+} + 2 H2O = 4[Co(H2O)6]{2+} + O2 + 4 H{+)
Zn + Na2MoO4 + H2SO4 = Mo2(SO4)3 + ZnSO4 + Na2SO4 + H2O =>
3 Zn + 2 Na2MoO4 + 8 H2SO4 = Mo2(SO4)3 + 3 ZnSO4 + 2 Na2SO4 + 8 H2O
CH3SH + CO = CH3CO(SCH3) + H2S =>
2 CH3SH + CO = CH3CO(SCH3) + H2S
Ca(OH)2 + Cu(CH3COO)2 = Ca(CH3COO)2 + Cu(OH)2 =>
Ca(OH)2 + Cu(CH3COO)2 = Ca(CH3COO)2 + Cu(OH)2
Al + (OH) = Al(OH)3 =>
Al + 3(OH) = Al(OH)3
K2SO4(aq) + Ba(NO3)2(aq) = K2(NO3)2(aq) + BaSO4(s) =>
K2SO4(aq) + Ba(NO3)2(aq) = K2(NO3)2(aq) + BaSO4(s)
SiO2 + C + F2 = SiF4 + CO =>
SiO2 + 2 C + 2 F2 = SiF4 + 2 CO
Cl2 + P2 = PCl2 =>
2 Cl2 + P2 = 2 PCl2
FeCr2 + K2CO3 + O2 = K2Cr2O4 + Fe2O3 + CO2 =>
4 FeCr2 + 4 K2CO3 + 9 O2 = 4 K2Cr2O4 + 2 Fe2O3 + 4 CO2
Sn(Cl)4 = Sn + Cl =>
Sn(Cl)4 = Sn + 4 Cl
Ba(IO4)2(aq) + K3PO4(aq) = Ba3(PO4)2 + KIO4(aq) =>
3 Ba(IO4)2(aq) + 2 K3PO4(aq) = Ba3(PO4)2 + 6 KIO4(aq)
Fe2O3 + H2SO4 + KI = FeSO4 + H2O + I2 + K2SO4 =>
Fe2O3 + 3 H2SO4 + 2 KI = 2 FeSO4 + 3 H2O + I2 + K2SO4
SeO2 + KOH = H2SeO3 + K2O =>
SeO2 + 2 KOH = H2SeO3 + K2O
NaBrO + NH3 = NaBr + N2 + H2O =>
3 NaBrO + 2 NH3 = 3 NaBr + N2 + 3 H2O
CH3CHOHCH3 + KMnO4 + H2SO4 = CH3COOH + K2SO4 + MnSO4 + H2O =>
10 CH3CHOHCH3 + 12 KMnO4 + 18 H2SO4 = 15 CH3COOH + 6 K2SO4 + 12 MnSO4 + 28 H2O
CuSO4 + FeCl2 = CuFe + Cl2SO4 =>
CuSO4 + FeCl2 = CuFe + Cl2SO4
MgCl2(aq) + AgNO3(aq) = AgCl(s) + Mg(NO3)2 =>
MgCl2(aq) + 2 AgNO3(aq) = 2 AgCl(s) + Mg(NO3)2
SO3{-2} + MnO4{-4} + H{+} = SO4{-2} + Mn{+2} + H2O =>
SO3{-2} + MnO4{-4} + 6 H{+} = SO4{-2} + Mn{+2} + 3 H2O
Sr(OH)2 + Co2(SO4)3 = Sr(SO4)2 + Co2(OH)3 =>
3 Sr(OH)2 + 2 Co2(SO4)3 = 3 Sr(SO4)2 + 2 Co2(OH)3
[Pb(OH)4] + H3O = [Pb(H2O)4]2 + H2O =>
2[Pb(OH)4] + 8 H3O = [Pb(H2O)4]2 + 8 H2O
MgBr2 + KOH = Mg(OH)2 + K{+} + Br{-} =>
MgBr2 + 2 KOH = Mg(OH)2 + 2 K{+} + 2 Br{-}
NaHCO3(s) + C2H4O2(aq) = CO2 + H2O + NaC2H3O2 =>
NaHCO3(s) + C2H4O2(aq) = CO2 + H2O + NaC2H3O2
Na + NiCO3 = Na2CO3 + Ni =>
2 Na + NiCO3 = Na2CO3 + Ni
H12C6O6 + O2 = CO2 + H2O =>
H12C6O6 + 6 O2 = 6 CO2 + 6 H2O
KMnO4 + NaOH + FeSO4 = K2MnO4 + Na2MnO4 + Fe(OH)3 + Na2SO4 =>
2 KMnO4 + 6 NaOH + 2 FeSO4 = K2MnO4 + Na2MnO4 + 2 Fe(OH)3 + 2 Na2SO4
NaOH + (NH4)Cl = NH3 + NaCl + H2O =>
NaOH + (NH4)Cl = NH3 + NaCl + H2O
Ca + Br2 = CaBr2 =>
Ca + Br2 = CaBr2
B2H6 + H2O2 = B2O3 + H2 =>
2 B2H6 + 3 H2O2 = 2 B2O3 + 9 H2
Na + P = PNa =>
Na + P = PNa
NH4HCO3(s) = NH3(g) + CO2(g) + H2O(g) =>
NH4HCO3(s) = NH3(g) + CO2(g) + H2O(g)
Hg + SnCl2 = HgCl2 + Sn =>
Hg + SnCl2 = HgCl2 + Sn
Équilibrer l'équation de toute réaction chimique
Équations équilibrées la veille |
Équations équilibrées sur12/10/24
Équations équilibrées sur01/09/24
-donnez-nous vos commentaires de votre expérience avec l'équilibreur d'équation chimique.