| Équations équilibrées la veille | Équations équilibrées le lendemain |
Sr(C2H3O2)2 + 2 KOH = Sr(OH)2 + 2 KC2H3O2
CO + H2 = C8H18 + H2O =>
8 CO + 17 H2 = C8H18 + 8 H2O
(NH4)3PO4 + LiOH = NH4OH + Li3PO4 =>
(NH4)3PO4 + 3 LiOH = 3 NH4OH + Li3PO4
Cr2O7 + H2C2O4 + H{+} = Cr{+} + CO2 + H2O =>
Cr2O7 + 6 H2C2O4 + 2 H{+} = 2 Cr{+} + 12 CO2 + 7 H2O
HNO3 + NH40 = NH4NO3 + H2O =>
82 HNO3 + 8 NH40 = 45 NH4NO3 + 111 H2O
K3PO4(aq) + CrCl3(aq) = KCl + CrPO4 =>
K3PO4(aq) + CrCl3(aq) = 3 KCl + CrPO4
Hg2C2O4(aq) + HCl = HgCl + H2C2O4 =>
Hg2C2O4(aq) + 2 HCl = 2 HgCl + H2C2O4
FeO(s) + C(s) = Fe(s) + CO(g) =>
FeO(s) + C(s) = Fe(s) + CO(g)
TiO2 + SiO2 + C = Ti5Si3 + CO =>
5 TiO2 + 3 SiO2 + 16 C = Ti5Si3 + 16 CO
Na + S + O2 = Na2S2O3 =>
4 Na + 4 S + 3 O2 = 2 Na2S2O3
FeSO4 + KSCN = Fe(SCN)2 + K2SO4 =>
FeSO4 + 2 KSCN = Fe(SCN)2 + K2SO4
Al(OH)3 + H2SO4 = Al2(SO4)3 + H2O =>
2 Al(OH)3 + 3 H2SO4 = Al2(SO4)3 + 6 H2O
FeCl3(aq) + F2(g) = FeF3(aq) + Cl2(g) =>
2 FeCl3(aq) + 3 F2(g) = 2 FeF3(aq) + 3 Cl2(g)
HCHO + H2O = CHOOH + H2 =>
HCHO + H2O = CHOOH + H2
FeSO4 = FeS + O3 =>
3 FeSO4 = 3 FeS + 4 O3
KOH + Mg3ClO = MgOH + K3ClO =>
3 KOH + Mg3ClO = 3 MgOH + K3ClO
Au2O + S8 + Ta2S5 = Au2S3 + Ta2O5 =>
20 Au2O + 5 S8 + 4 Ta2S5 = 20 Au2S3 + 4 Ta2O5
Cu2(ac) + NH3(ac) = Cu(NH3)4(ac) =>
Cu2(ac) + 8 NH3(ac) = 2 Cu(NH3)4(ac)
S8 + KNO3 = K2SO4 + SO2 + N2 =>
S8 + 8 KNO3 = 4 K2SO4 + 4 SO2 + 4 N2
Cd3(PO4)2 + NH4Cl = CdCl2 + (NH4)3PO4 =>
Cd3(PO4)2 + 6 NH4Cl = 3 CdCl2 + 2(NH4)3PO4
CH2O + Ca = (CHO)2Ca + H2 =>
2 CH2O + Ca = (CHO)2Ca + H2
NaOH + Cl2 = NaOCl + NaCl + H2O =>
2 NaOH + Cl2 = NaOCl + NaCl + H2O
CoBr3 + CaSO4 = CaBr2 + Co2(SO4)3 =>
2 CoBr3 + 3 CaSO4 = 3 CaBr2 + Co2(SO4)3
NH4Cl + PbN3 = NH4N + PbCl3 =>
3 NH4Cl + PbN3 = 3 NH4N + PbCl3
CH3COOH + NaHCO3 = Na3HCOONa + CO2 + H2O =>
5 CH3COOH + 32 NaHCO3 = 8 Na3HCOONa + 34 CO2 + 22 H2O
K2Cr2O7 + CH3CHO + HCl = CH3COOH + CrCl3 + KCl + H2O =>
K2Cr2O7 + 3 CH3CHO + 8 HCl = 3 CH3COOH + 2 CrCl3 + 2 KCl + 4 H2O
KBr + Na3[Co(NO2)6] = K3[Co(NO2)6] + NaBr =>
3 KBr + Na3[Co(NO2)6] = K3[Co(NO2)6] + 3 NaBr
C4H11N(l) + O2(g) = CO2(g) + H2O(l) + N2(g) =>
4 C4H11N(l) + 27 O2(g) = 16 CO2(g) + 22 H2O(l) + 2 N2(g)
Na3PO4 + Ba(NO3)2 = Ba2(PO4)3 + Na + NO3 =>
3 Na3PO4 + 2 Ba(NO3)2 = Ba2(PO4)3 + 9 Na + 4 NO3
Mg + N2 = Mg3N2 =>
3 Mg + N2 = Mg3N2
Al + O2 = Al2O3 =>
4 Al + 3 O2 = 2 Al2O3
NH4OH + HCl = HOH + NH4Cl =>
NH4OH + HCl = HOH + NH4Cl
MgCO3 + BaCl2 = BaCO3 + MgCl2 =>
MgCO3 + BaCl2 = BaCO3 + MgCl2
Al(NO3)3 + (NH4)3PO4 = AlPO4 + NH4NO3 =>
Al(NO3)3 + (NH4)3PO4 = AlPO4 + 3 NH4NO3
NaC2H3O2(aq) + HCl(aq) = NaCl(aq) + HC2H3O2 =>
NaC2H3O2(aq) + HCl(aq) = NaCl(aq) + HC2H3O2
Al(NO3)3 + (NH4)3PO4 = AlPO4 + NH4NO3 =>
Al(NO3)3 + (NH4)3PO4 = AlPO4 + 3 NH4NO3
Fe(CO)5 + OH = HFe(CO)4 + CO2(OH) =>
Fe(CO)5 + 2 OH = HFe(CO)4 + CO2(OH)
HgHCl = HHgCl =>
HgHCl = HHgCl
PbCl2 + Ca(OH)2 = Pb(OH)2 + CaCl2 =>
PbCl2 + Ca(OH)2 = Pb(OH)2 + CaCl2
C + S6 = CS2 =>
3 C + S6 = 3 CS2
C5H9O + O2 = CO2 + H2O =>
4 C5H9O + 27 O2 = 20 CO2 + 18 H2O
C + S8 = CS2 =>
4 C + S8 = 4 CS2
As2S3 + NO3{-} + H{+} = AsO4{-3} + SO4{-2} + NO2 + H2O =>
As2S3 + 28 NO3{-} + 16 H{+} = 2 AsO4{-3} + 3 SO4{-2} + 28 NO2 + 8 H2O
(NH4)2SO4 = N2 + H2O + NH3 + SO2 =>
3(NH4)2SO4 = N2 + 6 H2O + 4 NH3 + 3 SO2
(NH4)2[Co(SCN)4] + NaOH = Co(OH)2 + NaSCN + NH4SCN =>
(NH4)2[Co(SCN)4] + 2 NaOH = Co(OH)2 + 2 NaSCN + 2 NH4SCN
NH3(c) + Cl2 = N2 + HCl =>
2 NH3(c) + 3 Cl2 = N2 + 6 HCl
AgCN0 = Ag + C2N2 =>
2 AgCN0 = 2 Ag + C2N2
CH3CH2OH + K2Cr2O7 + H2SO4 = K2SO4 + Cr2(SO4)3 + CH3CHO + H2O =>
3 CH3CH2OH + K2Cr2O7 + 4 H2SO4 = K2SO4 + Cr2(SO4)3 + 3 CH3CHO + 7 H2O
MnO4 + H + KBr = KMn + Br2 + H2O =>
2 MnO4 + 16 H + 2 KBr = 2 KMn + Br2 + 8 H2O
Cu + Ca(NO3)2 = Cu(NO3)2Ca =>
Cu + Ca(NO3)2 = Cu(NO3)2Ca
| 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 |
| Équations équilibrées la veille | Équations équilibrées le lendemain |
Équations équilibrées sur12/16/24
Équations équilibrées sur01/15/24
-donnez-nous vos commentaires de votre expérience avec l'équilibreur d'équation chimique.
