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Équations chimiques équilibrées sur03/21/25

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[Cr(OH)4]{-} + H2O2 + FeSO4 = Fe(OH)3 + CrO42{-} + H2SO4 =>
2[Cr(OH)4]{-} + 101 H2O2 + 42 FeSO4 = 42 Fe(OH)3 + 2 CrO42{-} + 42 H2SO4

CoCO3 + NH4Cl + H2O2 + NH4OH = [Co(NH3)5Cl]Cl2 + H2O + CO2 =>
2 CoCO3 + 6 NH4Cl + H2O2 + 4 NH4OH = 2[Co(NH3)5Cl]Cl2 + 8 H2O + 2 CO2

Ca(HCO3)2 + Ca(OH)2 = CaCO3 + H2O =>
Ca(HCO3)2 + Ca(OH)2 = 2 CaCO3 + 2 H2O

KMnO4 + H3PO3 = H3PO4 + Mn3(PO4)2 + K3PO4 + H2O =>
6 KMnO4 + 15 H3PO3 = 9 H3PO4 + 2 Mn3(PO4)2 + 2 K3PO4 + 9 H2O

NaClO4 + K2S = Na2S + KClO4 =>
2 NaClO4 + K2S = Na2S + 2 KClO4

Cl + CH4 = CCl10 + HCl =>
14 Cl + CH4 = CCl10 + 4 HCl

LiNo3 + Na3Po4 = Li3Po4 + NaNo3 =>
3 LiNo3 + Na3Po4 = Li3Po4 + 3 NaNo3

KI2 + Br2 = I2 + KBr2 =>
KI2 + Br2 = I2 + KBr2

C6H6FN + HBF4 + NaNO2 = C6H4F2 + BF3 + N2 + NaOH + H2O =>
C6H6FN + HBF4 + NaNO2 = C6H4F2 + BF3 + N2 + NaOH + H2O

Cr(NO3)3(aq) + Na2S(aq) = NaNO3(aq) + Cr2S3(s) =>
2 Cr(NO3)3(aq) + 3 Na2S(aq) = 6 NaNO3(aq) + Cr2S3(s)

Hf + N4 = Hf3N4 =>
3 Hf + N4 = Hf3N4

KAlO2 + H2SO4 = H2O + KAl(SO4)2 =>
KAlO2 + 2 H2SO4 = 2 H2O + KAl(SO4)2

C6H12O6 + (Cr2O7){2-} + H{+} = Cr{3+} + CO2 + H2O =>
C6H12O6 + 4(Cr2O7){2-} + 32 H{+} = 8 Cr{3+} + 6 CO2 + 22 H2O

NH4 + BrO3 = NH4BrO3 =>
NH4 + BrO3 = NH4BrO3

KClO2 + CoCl2 + KOH = KCl + Co2O3 + H2O =>
KClO2 + 4 CoCl2 + 8 KOH = 9 KCl + 2 Co2O3 + 4 H2O

MgI2 + H2 = Mg + HI =>
MgI2 + H2 = Mg + 2 HI

CrCl3 + F2 = Cr3 + FCl =>
6 CrCl3 + 9 F2 = 2 Cr3 + 18 FCl

HMnO4 + H2O + SO2 = MnSO4 + H2SO4 =>
2 HMnO4 + 2 H2O + 5 SO2 = 2 MnSO4 + 3 H2SO4

NaOH*H2O + Fe(OH)3 = NaFeO2 + H2O =>
NaOH*H2O + Fe(OH)3 = NaFeO2 + 3 H2O

SiO2 + OH = OHSi3 + O2 =>
3 SiO2 + OH = OHSi3 + 3 O2

C4H8O(l) + O2 = CO2(g) + H2O =>
2 C4H8O(l) + 11 O2 = 8 CO2(g) + 8 H2O

CH3COONa + H2O = C2H6 + CO2 + NaOH =>
7 CH3COONa + 5 H2O = 4 C2H6 + 6 CO2 + 7 NaOH

H3PO4 + Na = NaH2PO4 + H =>
H3PO4 + Na = NaH2PO4 + H

Al(s) + OH{-}(aq) + H2O(l) = Al(OH)4{-})(aq) + H2(g) =>
2 Al(s) + 2 OH{-}(aq) + 6 H2O(l) = 2 Al(OH)4{-})(aq) + 3 H2(g)

C4H10O + NaCl = NaCH3O + C3H7Cl =>
C4H10O + NaCl = NaCH3O + C3H7Cl

As2S2 + HNO3 + H2O = H2SO4 + H3AsO4 + NO =>
3 As2S2 + 22 HNO3 + 4 H2O = 6 H2SO4 + 6 H3AsO4 + 22 NO

AgNo3(aq) + PbBr2(s) = AgBr(s) + Pb(No3)2(aq) =>
2 AgNo3(aq) + PbBr2(s) = 2 AgBr(s) + Pb(No3)2(aq)

HC2H3O2(aq) + NaOH(aq) = NaH(aq) + OHC2H3O2(aq) =>
HC2H3O2(aq) + NaOH(aq) = NaH(aq) + OHC2H3O2(aq)

CH3CH3 + O2 = CO2 + H2O =>
2 CH3CH3 + 7 O2 = 4 CO2 + 6 H2O

BN + ZrN + Zr = Zr6BN4 =>
BN + 3 ZrN + 3 Zr = Zr6BN4

Ca(C2H3O2)2 + (NH4)3PO4 = Ca3(PO4)2 + NH4(C2H3O2) =>
3 Ca(C2H3O2)2 + 2(NH4)3PO4 = Ca3(PO4)2 + 6 NH4(C2H3O2)

Na2B4O7*10H2O(borax) + HCl = NaCl + H3BO3 + H2O =>
Na2B4O7*10H2O(borax) + 2 HCl = 2 NaCl + 4 H3BO3 + 5 H2O

Mg + Cl12 = MgCl12 =>
Mg + Cl12 = MgCl12

NH4SCN + (FeCl3)2 = NH3 + HCl + Fe(SCN)3 =>
6 NH4SCN + (FeCl3)2 = 6 NH3 + 6 HCl + 2 Fe(SCN)3

KOH + Cl2 = KCl + K(ClO3) + H2O =>
6 KOH + 3 Cl2 = 5 KCl + K(ClO3) + 3 H2O

C23H25ClN2 + HCl = H26ClN2 + C23Cl =>
C23H25ClN2 + HCl = H26ClN2 + C23Cl

CaPO4 + SiO2 + C4 = Ca2SiO4 + CO + P4 =>
4 CaPO4 + 2 SiO2 + 3 C4 = 2 Ca2SiO4 + 12 CO + P4

Br2(aq) + Cl{-}(aq) = Cl2(aq) + Br{-}(aq) =>
Br2(aq) + 2 Cl{-}(aq) = Cl2(aq) + 2 Br{-}(aq)

Ba(NO3)3 + C2H5O2N = BaO + N2 + CO2 + H2O =>
18 Ba(NO3)3 + 32 C2H5O2N = 18 BaO + 43 N2 + 64 CO2 + 80 H2O

Hg + ClO3{-} = HgO + Cl{-} =>
3 Hg + ClO3{-} = 3 HgO + Cl{-}

HNO2 + K2Cr2O7 + H2SO4 = HNO3 + K2SO4 + Cr2(SO4)3 + H2O =>
3 HNO2 + K2Cr2O7 + 4 H2SO4 = 3 HNO3 + K2SO4 + Cr2(SO4)3 + 4 H2O

CuFeS2(s) + O2(g) = FeO(s) + SO2(s) + Cu(s) =>
2 CuFeS2(s) + 5 O2(g) = 2 FeO(s) + 4 SO2(s) + 2 Cu(s)

C2H5OH + O2 = CO2 + H2O =>
C2H5OH + 3 O2 = 2 CO2 + 3 H2O

Cu2O + C = Cu2 + CO2 =>
2 Cu2O + C = 2 Cu2 + CO2

Na2CrO4 + NaBr + H2SO4 = Br2 + Na2SO4 + Cr2(SO4)3 + H2O =>
2 Na2CrO4 + 6 NaBr + 8 H2SO4 = 3 Br2 + 5 Na2SO4 + Cr2(SO4)3 + 8 H2O

CuO + NH4OH + (NH4)2SO4 = (Cu(NH3)4)SO4 + H2O =>
CuO + 2 NH4OH + (NH4)2SO4 = (Cu(NH3)4)SO4 + 3 H2O

KCl + Zn3(PO4)2 = K3(PO4) + ZnCl2 =>
6 KCl + Zn3(PO4)2 = 2 K3(PO4) + 3 ZnCl2

I3{-} + MnO4{-} + H2O = IO2{-} + MnO2 + OH{-} =>
3 I3{-} + 10 MnO4{-} + 2 H2O = 9 IO2{-} + 10 MnO2 + 4 OH{-}

Br2 + HI = I + HBr =>
Br2 + 2 HI = 2 I + 2 HBr

H4 + O20 = H2O =>
10 H4 + O20 = 20 H2O

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