Équations équilibrées la veille | Équations équilibrées le lendemain |
NH4Cl(s) + NaOH(aq) = NaCl(ac) + H2O(l) + NH3(g)
Cu{+} + I2{-} = CuI + I2 =>
2 Cu{+} + 2 I2{-} = 2 CuI + I2
MgSO4 + CaCl2 = CaSO4 + MgCl2 =>
MgSO4 + CaCl2 = CaSO4 + MgCl2
La4[Fe(CN)6]3 + La2(Cr5O16)3 + H2S2O8 + La2(S2O3)3 = La[Fe(S2O7)3] + Cr2(S4O6)3 + La(NO3)3 + C10H8 + H2O =>
50 La4[Fe(CN)6]3 + 16 La2(Cr5O16)3 + 843 H2S2O8 + 109 La2(S2O3)3 = 150 La[Fe(S2O7)3] + 120 Cr2(S4O6)3 + 300 La(NO3)3 + 90 C10H8 + 483 H2O
Cu(OAc)2*H2O + C2H8N2 + KI + H2O = [Cu(H2NCH2CH2NH2)2(H2O)2]I2 + K(OAc) =>
Cu(OAc)2*H2O + 2 C2H8N2 + 2 KI + H2O = [Cu(H2NCH2CH2NH2)2(H2O)2]I2 + 2 K(OAc)
SO3 + H2O = H2SO4 =>
SO3 + H2O = H2SO4
K2[PtCl6] + Pt + KCl = K2[PtCl4] =>
K2[PtCl6] + Pt + 2 KCl = 2 K2[PtCl4]
SbS + O2 = Sb2O3 + SO2 =>
4 SbS + 7 O2 = 2 Sb2O3 + 4 SO2
NaAl(OH)4 + NH4Cl = NaCl + AlCl3 + NH3 + H2O =>
NaAl(OH)4 + 4 NH4Cl = NaCl + AlCl3 + 4 NH3 + 4 H2O
Li + (NH3) = LiNH2 + H2 =>
2 Li + 2(NH3) = 2 LiNH2 + H2
Ca(NO3)2 + (NH4)2SO4 = CaSO4 + (NH4)2(NO3)2 =>
Ca(NO3)2 + (NH4)2SO4 = CaSO4 + (NH4)2(NO3)2
Fe + Cl = FeCl3 =>
Fe + 3 Cl = FeCl3
Al + NO3{-} + OH{-} + H2O = Al(OH)4{-} + NH3 =>
8 Al + 3 NO3{-} + 5 OH{-} + 18 H2O = 8 Al(OH)4{-} + 3 NH3
NH4NO2(aq) = N2 + H2O =>
NH4NO2(aq) = N2 + 2 H2O
H2SO4BaCO3 = BaSO4CO2H2O =>
H2SO4BaCO3 = BaSO4CO2H2O
Mg + HCl = MgCl2 + H2 =>
Mg + 2 HCl = MgCl2 + H2
NH4Cl + C4H6O4Hg = C2H7NO2 + HgCl2 =>
2 NH4Cl + C4H6O4Hg = 2 C2H7NO2 + HgCl2
C12H25SO3Na = CH4 + CH3Na + C + H2SO3 =>
C12H25SO3Na = 5 CH4 + CH3Na + 6 C + H2SO3
CH2ClCH2CH2CH3 + NaOH = CH3CHCHCH3 + NaCl + H2O =>
CH2ClCH2CH2CH3 + NaOH = CH3CHCHCH3 + NaCl + H2O
K2S2O5 + H2O = KSO3H =>
K2S2O5 + H2O = 2 KSO3H
CuSO4 + HPO2 + H2O = CuH + H3PO4 + H2SO4 =>
2 CuSO4 + 3 HPO2 + 6 H2O = 2 CuH + 3 H3PO4 + 2 H2SO4
Hg2Cl2 + HCl = Hg2Cl3 + H =>
Hg2Cl2 + HCl = Hg2Cl3 + H
RCH2OH + MnO4{-} = RCHO + MnO2 + H2O + OH{-} =>
3 RCH2OH + 2 MnO4{-} = 3 RCHO + 2 MnO2 + 2 H2O + 2 OH{-}
Ta + HNO3 + HF = NO + H2TaF7 + H2O =>
3 Ta + 5 HNO3 + 21 HF = 5 NO + 3 H2TaF7 + 10 H2O
SO3 + K2O = K2SO4 =>
SO3 + K2O = K2SO4
KMnO4 + SO2 + H2O = MnSO4 + KHSO4 + H2S2O6 =>
2 KMnO4 + 6 SO2 + 2 H2O = 2 MnSO4 + 2 KHSO4 + H2S2O6
PbCl2 + KOH = Pb(OH)2 + KCl =>
PbCl2 + 2 KOH = Pb(OH)2 + 2 KCl
H2O + Cl2O = HOCl =>
H2O + Cl2O = 2 HOCl
Ba(NO3)2 + Na3PO4 = Ba3(PO4)2 + NaNO3 =>
3 Ba(NO3)2 + 2 Na3PO4 = Ba3(PO4)2 + 6 NaNO3
C793H11OH + O51 = CO2 + H2O =>
51 C793H11OH + 1591 O51 = 40443 CO2 + 306 H2O
NaOH + CrBr2 = NaBr2 + CrOH =>
NaOH + CrBr2 = NaBr2 + CrOH
CuSO4(aq) + KCl(aq) = K2SO4 + CuCl2 =>
CuSO4(aq) + 2 KCl(aq) = K2SO4 + CuCl2
Pt + HCl = Pt(Cl)2 + H2 =>
Pt + 2 HCl = Pt(Cl)2 + H2
Na2SO4 + BeCl2 = Na2Cl2 + BeSO4 =>
Na2SO4 + BeCl2 = Na2Cl2 + BeSO4
C12H24 + C8H18 = C20H42 =>
C12H24 + C8H18 = C20H42
C6H8O7 + O2 = CO2 + H2O =>
2 C6H8O7 + 9 O2 = 12 CO2 + 8 H2O
Pd + Bi + K = KPd10Bi20 =>
10 Pd + 20 Bi + K = KPd10Bi20
H2O + NH2OH + e = NH4OH + OH{-} =>
2 H2O + NH2OH + 2e = NH4OH + 2 OH{-}
Fe(NO3)2 + K2S = KNO3 + FeS =>
Fe(NO3)2 + K2S = 2 KNO3 + FeS
Pb(NO3)2 + KI = PbI2 + KNO3 =>
Pb(NO3)2 + 2 KI = PbI2 + 2 KNO3
(N2H5)2Cr(SO4)2*H2O + HCl + O2 = CrCl(SO4) + N2H5Cl + H2SO4 + H2O =>
4(N2H5)2Cr(SO4)2*H2O + 12 HCl + O2 = 4 CrCl(SO4) + 8 N2H5Cl + 4 H2SO4 + 6 H2O
BF3 + H2O = HF + H3BO3 =>
BF3 + 3 H2O = 3 HF + H3BO3
Ce(OH)4 + H2O2 = Ce(OH)3OOH + H2O =>
Ce(OH)4 + H2O2 = Ce(OH)3OOH + H2O
SO4H2 + ClNa = (SO4)Na2 + ClH =>
SO4H2 + 2 ClNa = (SO4)Na2 + 2 ClH
(C6H4NO2)COOH + C2H5OH = (C6H4NO2)COOC2H5 + H2O =>
(C6H4NO2)COOH + C2H5OH = (C6H4NO2)COOC2H5 + H2O
MgCO3 = CO2 + MgO =>
MgCO3 = CO2 + MgO
HNO3 + NH3 = (NH4) + (NO3) =>
HNO3 + NH3 = (NH4) + (NO3)
CaO + CaC2 = Ca2C2O =>
CaO + CaC2 = Ca2C2O
KOH + C4H8O2 = C2H3O2K + C2H6O =>
KOH + C4H8O2 = C2H3O2K + C2H6O
H3PO2 + Ag3AsO4 + H2O = H3PO4 + Ag + H3AsO4 =>
3 H3PO2 + 4 Ag3AsO4 + 6 H2O = 3 H3PO4 + 12 Ag + 4 H3AsO4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 |
Équations équilibrées la veille | Équations équilibrées le lendemain |
Équations équilibrées sur06/06/25
Équations équilibrées sur07/06/24
-donnez-nous vos commentaires de votre expérience avec l'équilibreur d'équation chimique.