Equations balanced on the previous day | Equations balanced on the next day |
KClO{-}3 = KCl + O{-}2
NiCl2 + HNO3 = Ni(NO3)2 + Cl2 + NO + H2O =>
3 NiCl2 + 8 HNO3 = 3 Ni(NO3)2 + 3 Cl2 + 2 NO + 4 H2O
SO2 + OH2O = H2SO4 =>
SO2 + OH2O = H2SO4
Sn(NO3)4 + Cd3(PO4)2 = Cd(NO3)2 + Sn3(PO4)4 =>
3 Sn(NO3)4 + 2 Cd3(PO4)2 = 6 Cd(NO3)2 + Sn3(PO4)4
(CN)2 + F2 = (CF4) + NF3 =>
(CN)2 + 7 F2 = 2(CF4) + 2 NF3
H2O + P4 = H2PO2 + PH3 =>
24 H2O + 5 P4 = 12 H2PO2 + 8 PH3
CH5N + C6H5ClO2S = C7H9NO2S + HCl =>
CH5N + C6H5ClO2S = C7H9NO2S + HCl
Na2CO3(aq) + CoCl2 = CoCO3 + NaCl =>
Na2CO3(aq) + CoCl2 = CoCO3 + 2 NaCl
C2 + H2O = COH2 =>
C2 + 2 H2O = 2 COH2
HCl + NaCO3H = NaClCO3 + H2 =>
HCl + NaCO3H = NaClCO3 + H2
HI + KMnO4 + H2SO4 = I2 + MnS04 + K2SO4 + H2O =>
62 HI + 2 KMnO4 + 9 H2SO4 = 31 I2 + 2 MnS04 + K2SO4 + 40 H2O
H2O + KI + KIO3 + UO2(NO3)2 = I2 + KNO3 + UO2(OH)2 =>
3 H2O + 5 KI + KIO3 + 3 UO2(NO3)2 = 3 I2 + 6 KNO3 + 3 UO2(OH)2
NiCl2 + HNO3 = NiNO3 + HCl2 =>
NiCl2 + HNO3 = NiNO3 + HCl2
NaCl + NaOH = Na2ClOH =>
NaCl + NaOH = Na2ClOH
NaCl + NaOH = Na2ClOH =>
NaCl + NaOH = Na2ClOH
NaCO3H + HCl = NaCl + CO2 + H2O =>
NaCO3H + HCl = NaCl + CO2 + H2O
CoCl2*6H2O + Cl{-} = [CoCl4]{-2} + H2O =>
CoCl2*6H2O + 2 Cl{-} = [CoCl4]{-2} + 6 H2O
HC2H3O2 + Cu = Cu(CO)2 + H2 =>
HC2H3O2 + Cu = Cu(CO)2 + 2 H2
HI + KMnO4 + H2SO4 = I2 + MnS04 + K2SO4 + H2O =>
62 HI + 2 KMnO4 + 9 H2SO4 = 31 I2 + 2 MnS04 + K2SO4 + 40 H2O
NiCl2 + HNO3 = NiNO3 + HCl2 =>
NiCl2 + HNO3 = NiNO3 + HCl2
[HgI4]{2-} + OH{-} + NH4{+} = [Hg2N]I + H2O + I{-} =>
2[HgI4]{2-} + 4 OH{-} + NH4{+} = [Hg2N]I + 4 H2O + 7 I{-}
C2H2 + AgNO3 = CHCAg + HNO3 =>
C2H2 + AgNO3 = CHCAg + HNO3
Ca(S) + HCl(aq) = CaCl2(S) + H2(g) =>
Ca(S) + 2 HCl(aq) = CaCl2(S) + H2(g)
K2OCr2O7 + SnCl2 + HCl = CrCl3 + SnCl4 + KCl4 + H2O =>
K2OCr2O7 + SnCl2 + 16 HCl = 2 CrCl3 + SnCl4 + 2 KCl4 + 8 H2O
C2 + H2O = COH2 =>
C2 + 2 H2O = 2 COH2
Ca(S) + HCl(aq) = CaCl2(S) + H2(g) =>
Ca(S) + 2 HCl(aq) = CaCl2(S) + H2(g)
H13 + C = HC29 =>
H13 + 377 C = 13 HC29
Na2CO3(aq) + CoCl2 = CoCO3(s) + NaCl =>
Na2CO3(aq) + CoCl2 = CoCO3(s) + 2 NaCl
I2(aq) + NaCl(aq) = Cl2(aq) + NaI(aq) =>
I2(aq) + 2 NaCl(aq) = Cl2(aq) + 2 NaI(aq)
C2952H4664N816O832S8Fe4 + CsClO3 + Li3PO4 = Li4Fe(CN)6 + CO2 + CsNO3 + LiHCl2 + H3PO4 + CsCl + H2S + H2O =>
3 C2952H4664N816O832S8Fe4 + 9320 CsClO3 + 412 Li3PO4 = 12 Li4Fe(CN)6 + 8784 CO2 + 2376 CsNO3 + 1188 LiHCl2 + 412 H3PO4 + 6944 CsCl + 24 H2S + 5760 H2O
NiCl2 + HNO3 = NiNO3 + HCl2 =>
NiCl2 + HNO3 = NiNO3 + HCl2
BaCl2 + KH2Po4 = Ba(H2Po4)2 + KCl =>
BaCl2 + 2 KH2Po4 = Ba(H2Po4)2 + 2 KCl
HI + KMnO4 + H2SO4 = I2 + MnS04 + K2SO4 + H2O =>
62 HI + 2 KMnO4 + 9 H2SO4 = 31 I2 + 2 MnS04 + K2SO4 + 40 H2O
HI + KMnO4 + H2SO4 = I2 + MnS04 + K2SO4 + H2O =>
62 HI + 2 KMnO4 + 9 H2SO4 = 31 I2 + 2 MnS04 + K2SO4 + 40 H2O
K2CrO7 + HCl = Cr + H2O + Cl2 + K2 =>
K2CrO7 + 14 HCl = Cr + 7 H2O + 7 Cl2 + K2
NH4I + Pb(ClO3)2 = NH4(ClO3)2 + PbI =>
NH4I + Pb(ClO3)2 = NH4(ClO3)2 + PbI
K2Cr2O7 + H2O + S = SO2 + KOH + HCr2O3 =>
4 K2Cr2O7 + 6 H2O + 7 S = 7 SO2 + 8 KOH + 4 HCr2O3
NaCl + NaOH = Na2ClOH =>
NaCl + NaOH = Na2ClOH
C8H10N4O2 + NH4ClO4 = Cl2 + H2O + N2 + CO =>
4 C8H10N4O2 + 22 NH4ClO4 = 11 Cl2 + 64 H2O + 19 N2 + 32 CO
Na2CO3(aq) + CoCl2 = CoCO3(s) + NaCl =>
Na2CO3(aq) + CoCl2 = CoCO3(s) + 2 NaCl
Ca(S) + HCl(aq) = CaCl2(S) + H2(g) =>
Ca(S) + 2 HCl(aq) = CaCl2(S) + H2(g)
C27H50O6 + CH3O = C19H36O2 + C3H8O3 =>
17 C27H50O6 + 198 CH3O = 21 C19H36O2 + 86 C3H8O3
C2H4(OH)2 + Na = C2H4ONaOH + H2 =>
2 C2H4(OH)2 + 2 Na = 2 C2H4ONaOH + H2
KMnO4 + Na2S + HCl = S + NaCl + H2O + KCl + MnCl2 =>
2 KMnO4 + 5 Na2S + 16 HCl = 5 S + 10 NaCl + 8 H2O + 2 KCl + 2 MnCl2
Al3 + H2O = Al(H2O) =>
Al3 + 3 H2O = 3 Al(H2O)
Na2SiO3 + NH4Cl = NaCl + H2O + SiO2 + NH3 =>
Na2SiO3 + 2 NH4Cl = 2 NaCl + H2O + SiO2 + 2 NH3
Li2O4 + H3PO4 = H2O2 + LiPO3 =>
Li2O4 + 2 H3PO4 = 3 H2O2 + 2 LiPO3
HI + KMnO4 + H2SO4 = I2 + MnS04 + K2SO4 + H2O =>
62 HI + 2 KMnO4 + 9 H2SO4 = 31 I2 + 2 MnS04 + K2SO4 + 40 H2O
FeC2O4 + H2O2 + H2C2O4*2H20 + K2C2O4*H2O = K3[Fe(C2O4)3]*3H2O + H2O =>
2 FeC2O4 + 21 H2O2 + H2C2O4*2H20 + 3 K2C2O4*H2O = 2 K3[Fe(C2O4)3]*3H2O + 39 H2O
HBrO3 + Ce(OH)3 = Ce(BrO3)3 + H2O =>
3 HBrO3 + Ce(OH)3 = Ce(BrO3)3 + 3 H2O
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Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/24/23
Equations balanced on 12/24/22
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