Equations balanced on the previous day | Equations balanced on the next day |
HS + PbCl = HCl + PbS
MnO4 + SO2 + KOH = MnO2 + K2SO4 + H2O =>
MnO4 + 2 SO2 + 4 KOH = MnO2 + 2 K2SO4 + 2 H2O
NaH2PO3 + H2SO4 + KMnO4 = MnSO4 + NaH2PO4 + K2SO4 + H2O =>
5 NaH2PO3 + 3 H2SO4 + 2 KMnO4 = 2 MnSO4 + 5 NaH2PO4 + K2SO4 + 3 H2O
CsHCO3 + H2SO4 = CO2 + H2O + CsHSO4 =>
CsHCO3 + H2SO4 = CO2 + H2O + CsHSO4
Al2(SO4)3 + NH3 + H2O = Al(OH)3 + (NH4)2SO4 =>
Al2(SO4)3 + 6 NH3 + 6 H2O = 2 Al(OH)3 + 3(NH4)2SO4
Ag2S3 + HNO3 + H2O = H3AgO4 + NO + H2SO4 =>
3 Ag2S3 + 28 HNO3 + 4 H2O = 6 H3AgO4 + 28 NO + 9 H2SO4
Co(NH3)5CO3{+} + H3O{+} = Co(NH3)5(H2O){3+} + H2O + CO2 =>
Co(NH3)5CO3{+} + 2 H3O{+} = Co(NH3)5(H2O){3+} + 2 H2O + CO2
BaCl2 + Na2CO3 = BaCO3(s) + NaCl =>
BaCl2 + Na2CO3 = BaCO3(s) + 2 NaCl
Zn + S = ZnS =>
Zn + S = ZnS
MnO4{-} + S2O3{-2} + H{+} = Mn{+2} + SO4{-2} + H2O =>
8 MnO4{-} + 5 S2O3{-2} + 14 H{+} = 8 Mn{+2} + 10 SO4{-2} + 7 H2O
HCl + FeO = H2 + FeCl2 + O2 =>
4 HCl + 2 FeO = 2 H2 + 2 FeCl2 + O2
Fe + H2O = H + Fe2O33 =>
2 Fe + 33 H2O = 66 H + Fe2O33
FeBr3(aq) + NaOH(aq) = Fe(OH)3 + BrNa =>
FeBr3(aq) + 3 NaOH(aq) = Fe(OH)3 + 3 BrNa
Cu(OH)Cl + NaOH = Cu(OH)2 + NaCl =>
Cu(OH)Cl + NaOH = Cu(OH)2 + NaCl
Sb2O5 + NaOH = NaSbO3 + H2O =>
Sb2O5 + 2 NaOH = 2 NaSbO3 + H2O
Bi + KOH = BiOH + K =>
Bi + KOH = BiOH + K
FeBr3(aq) + NaOH(aq) = Fe(OH)3 + BrNa =>
FeBr3(aq) + 3 NaOH(aq) = Fe(OH)3 + 3 BrNa
CH3COO{-} + Fe{3+} + H2O = Fe(OH)2CH3OO + CH3COOH =>
6 CH3COO{-} + 2 Fe{3+} + 6 H2O = 2 Fe(OH)2CH3OO + 5 CH3COOH
C6H5C2H3 + KMnO4 + H2O = C6H5COOH + KOH + MnO3 =>
7 C6H5C2H3 + 40 KMnO4 + 16 H2O = 8 C6H5COOH + 40 KOH + 40 MnO3
Zn + K2CO3 + H2O = K2[Zn(CO3)2] + KOH + H2 =>
Zn + 2 K2CO3 + 2 H2O = K2[Zn(CO3)2] + 2 KOH + H2
YOMaMa = YOMa2 =>
YOMaMa = YOMa2
(CH3)3CNH3Cl + H2O = H3O + (CH3)3CNH2Cl =>
(CH3)3CNH3Cl + H2O = H3O + (CH3)3CNH2Cl
LiOH + Zr(OH)4 = Li2ZrO3 + H2O =>
2 LiOH + Zr(OH)4 = Li2ZrO3 + 3 H2O
FeBr3(aq) + NaOH(aq) = Fe(OH)3 + BrNa =>
FeBr3(aq) + 3 NaOH(aq) = Fe(OH)3 + 3 BrNa
KMnO4 + FeCl3 = KCl + MnCl2 + Fe + O2 =>
KMnO4 + FeCl3 = KCl + MnCl2 + Fe + 2 O2
S + HNO3 = H2O + H2SO4 + NO2 =>
S + 6 HNO3 = 2 H2O + H2SO4 + 6 NO2
CuO + H2SO4 = Cu + SO4 + H2O =>
CuO + H2SO4 = Cu + SO4 + H2O
K + [Fe(C2O4)3]3 + H2O = K3[Fe(C2O4)3]*3H2O =>
9 K + [Fe(C2O4)3]3 + 9 H2O = 3 K3[Fe(C2O4)3]*3H2O
LiOH + Zr(OH)4 = Li2ZrO3 + H2O =>
2 LiOH + Zr(OH)4 = Li2ZrO3 + 3 H2O
FeBr3(aq) + NaOH(aq) = Fe(OH)3 + BrNa =>
FeBr3(aq) + 3 NaOH(aq) = Fe(OH)3 + 3 BrNa
MnO2 + KOH + O2Cl2 = KMnO4 + KCl + H2O =>
2 MnO2 + 4 KOH + O2Cl2 = 2 KMnO4 + 2 KCl + 2 H2O
NaNO2 + CaCl2 = Ca(NO2)2 + NaCl =>
2 NaNO2 + CaCl2 = Ca(NO2)2 + 2 NaCl
FeBr3(aq) + NaOH(aq) = Fe(OH)3 + BrNa =>
FeBr3(aq) + 3 NaOH(aq) = Fe(OH)3 + 3 BrNa
SO2 + KMnO4 + H2O = MnSO4 + KS + H2SO4 =>
6 SO2 + KMnO4 + 4 H2O = MnSO4 + KS + 4 H2SO4
ClO{-} + Cr3{+} + OH{-} = CrO42{-} + Cl{-} + H2O =>
124 ClO{-} + Cr3{+} + 4 OH{-} = 3 CrO42{-} + 124 Cl{-} + 2 H2O
Na2O + CO2 = Na2CO3 =>
Na2O + CO2 = Na2CO3
FeBr3(aq) + NaOH(aq) = Fe(OH)3 + BrNa =>
FeBr3(aq) + 3 NaOH(aq) = Fe(OH)3 + 3 BrNa
C6H5C2H3 + KMnO4 + H2O = C6H5COOH + KOH + MnO3 =>
7 C6H5C2H3 + 40 KMnO4 + 16 H2O = 8 C6H5COOH + 40 KOH + 40 MnO3
CuFeS2 + HNO3 = Cu(NO3)2 + Fe(NO3)3 + H2O + S + NO =>
3 CuFeS2 + 20 HNO3 = 3 Cu(NO3)2 + 3 Fe(NO3)3 + 10 H2O + 6 S + 5 NO
Cr2O7{2-} + H{+} + C4H9OH = Cr{3+} + CH3COOH + H2O =>
4 Cr2O7{2-} + 32 H{+} + 3 C4H9OH = 8 Cr{3+} + 6 CH3COOH + 19 H2O
FeBr3(aq) + NaOH(aq) = Fe(OH)3 + BrNa =>
FeBr3(aq) + 3 NaOH(aq) = Fe(OH)3 + 3 BrNa
K2Cr2O7 + NaOH + Na2SO3 = Na2CrO4 + K2SO3 + H2O =>
K2Cr2O7 + 2 NaOH + Na2SO3 = 2 Na2CrO4 + K2SO3 + H2O
MnSO4 + NaBiO3 + HNO3 = HMnO4 + Bi(NO3)3 + NaSO4 + NaNO3 + H2O =>
MnSO4 + 3 NaBiO3 + 11 HNO3 = HMnO4 + 3 Bi(NO3)3 + NaSO4 + 2 NaNO3 + 5 H2O
KMnO4 + H2C2O4 + HCl = KCl + MnCl + CO2 + H2O =>
KMnO4 + 3 H2C2O4 + 2 HCl = KCl + MnCl + 6 CO2 + 4 H2O
FeBr3(aq) + NaOH(aq) = Fe(OH)3 + BrNa =>
FeBr3(aq) + 3 NaOH(aq) = Fe(OH)3 + 3 BrNa
CH3CHO + CH3MgCl = CH3CH3CHOMgCl =>
CH3CHO + CH3MgCl = CH3CH3CHOMgCl
(CN)2 + H2O = H2C2O4 + NH3 =>
(CN)2 + 4 H2O = H2C2O4 + 2 NH3
Cu3(SO4)2 + H = H2SO4 + Cu =>
Cu3(SO4)2 + 4 H = 2 H2SO4 + 3 Cu
FeBr3(aq) + NaOH(aq) = Fe(OH)3 + BrNa =>
FeBr3(aq) + 3 NaOH(aq) = Fe(OH)3 + 3 BrNa
NaBr + F2 = Na2F + Br2 =>
4 NaBr + F2 = 2 Na2F + 2 Br2
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/24/23
Equations balanced on 12/24/22
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