Equations balanced on the previous day | Equations balanced on the next day |
HF + NaHCO3 = NaF + H2O + CO2
Na2Cr2O7 + HCl + Fe(SO4) = CrCl3 + NaCl + Fe2(SO4)3 + FeCl3 + H2O =>
Na2Cr2O7 + 14 HCl + 6 Fe(SO4) = 2 CrCl3 + 2 NaCl + 2 Fe2(SO4)3 + 2 FeCl3 + 7 H2O
Ca(OH)2*4H2O + (NH4)2HPO4 + NH4OH = Ca10(PO4)(OH)2 + NH4NO3 + H2O =>
80 Ca(OH)2*4H2O + 8(NH4)2HPO4 + 14 NH4OH = 8 Ca10(PO4)(OH)2 + 15 NH4NO3 + 433 H2O
Tl2O3 + HCl = TlCl + Cl2 + H2O =>
Tl2O3 + 6 HCl = 2 TlCl + 2 Cl2 + 3 H2O
H2SO3 + H2O2 = H2SO4 + H2O =>
H2SO3 + H2O2 = H2SO4 + H2O
CaC2 + H2O + CO2 = Ca(OH)2 + CH2CHO2H =>
4 CaC2 + 14 H2O + 2 CO2 = 4 Ca(OH)2 + 5 CH2CHO2H
H3PO4(aq) + Ca(OH)2 = Ca3(PO4)2(aq) + H2O(l) =>
2 H3PO4(aq) + 3 Ca(OH)2 = Ca3(PO4)2(aq) + 6 H2O(l)
RbI + CuCl2 = RbCl + CuI2 =>
2 RbI + CuCl2 = 2 RbCl + CuI2
Cu(s) + H3O{+}(aq) + NO3{-}(aq) = Cu{2+}(aq) + NO2(g) + H2O(l) =>
Cu(s) + 4 H3O{+}(aq) + 2 NO3{-}(aq) = Cu{2+}(aq) + 2 NO2(g) + 6 H2O(l)
H2SO4 + KMnO4 + H2O2 = HMnO4 + KSO4 + H2O =>
2 H2SO4 + 2 KMnO4 + H2O2 = 2 HMnO4 + 2 KSO4 + 2 H2O
CaCl2(aq) + H2O(l) = Ca(OH)2(aq) + HCl(l) =>
CaCl2(aq) + 2 H2O(l) = Ca(OH)2(aq) + 2 HCl(l)
C7H6O + C3H6O = C17H12O + H2O =>
19 C7H6O + C3H6O = 8 C17H12O + 12 H2O
Fe(HCO3)3 = Fe(OH)3 + CO2 =>
Fe(HCO3)3 = Fe(OH)3 + 3 CO2
Mg3N2 + H2O(l) = Mg(OH)2 + NH3(g) =>
Mg3N2 + 6 H2O(l) = 3 Mg(OH)2 + 2 NH3(g)
H3NaO5S + Na2CO3 = CO2 + SO3 + NaOH =>
H3NaO5S + Na2CO3 = CO2 + SO3 + 3 NaOH
SnO2 + Fe + S = SnS2 + Fe2O3 =>
3 SnO2 + 4 Fe + 6 S = 3 SnS2 + 2 Fe2O3
SnS + Na2S = SnS2Na2 =>
SnS + Na2S = SnS2Na2
H2SO4 + NaOH = Na2SO4 + H2O =>
H2SO4 + 2 NaOH = Na2SO4 + 2 H2O
S2Fe + O2 = Fe2O3 + SO =>
4 S2Fe + 7 O2 = 2 Fe2O3 + 8 SO
CH3(CH2)14COONa + CaCl2 = CH3(CH2)14COONaCl3 + Ca =>
2 CH3(CH2)14COONa + 3 CaCl2 = 2 CH3(CH2)14COONaCl3 + 3 Ca
Cr2O7{-2} + H{+} + Zn = Cr{+3} + water + Zn{+2} =>
Cr2O7{-2} + 14 H{+} + 3 Zn = 2 Cr{+3} + 7 H2O + 3 Zn{+2}
B2F3 + LiSO3 = B2(SO3)3 + LiF =>
B2F3 + 3 LiSO3 = B2(SO3)3 + 3 LiF
Li + ZnP = LiP + Zn =>
Li + ZnP = LiP + Zn
H2O + CaBr2 = H2Br2 + CaO =>
H2O + CaBr2 = H2Br2 + CaO
Pb3O4 + H2 = Pb + OH =>
Pb3O4 + 2 H2 = 3 Pb + 4 OH
C15O2NH15 + NaBH4 = C15O2NH18 + NaBH3 =>
C15O2NH15 + 3 NaBH4 = C15O2NH18 + 3 NaBH3
HCOOH + C3H7OH = H2O + C2H3O2HCO =>
6 HCOOH + C3H7OH = 4 H2O + 3 C2H3O2HCO
Hg + NO3{-} + H{+} + Cl{-} = HgCl4 + NO + H2O =>
3 Hg + 4 NO3{-} + 16 H{+} + 12 Cl{-} = 3 HgCl4 + 4 NO + 8 H2O
C12H22O11 + O2 = C2O + H2O =>
C12H22O11 + 3 O2 = 6 C2O + 11 H2O
Ca(NO3)2 + (NH4)3PO4 = PO4(NO3)2 + Ca(NH4)3 =>
Ca(NO3)2 + (NH4)3PO4 = PO4(NO3)2 + Ca(NH4)3
IO + SO3 = I2 + SO4 =>
2 IO + 2 SO3 = I2 + 2 SO4
Hg(NO3)2 + LiCl = HgCl2 + LiNO3 =>
Hg(NO3)2 + 2 LiCl = HgCl2 + 2 LiNO3
NaF + HCl = NaCl + HF =>
NaF + HCl = NaCl + HF
RbOH + H2CO3 = H2O + Rb2CO3 =>
2 RbOH + H2CO3 = 2 H2O + Rb2CO3
Cu(NO3)2 + SrBr2 = CuBr2 + Sr(NO3)2 =>
Cu(NO3)2 + SrBr2 = CuBr2 + Sr(NO3)2
NH2NH2 + H2O = NH2NH3 + OH =>
NH2NH2 + H2O = NH2NH3 + OH
C8H8O2 + NaOH = C6H5ONa + H2O + CH3COONa =>
C8H8O2 + 2 NaOH = C6H5ONa + H2O + CH3COONa
H3BO3 = H2O + H4B6O11 =>
6 H3BO3 = 7 H2O + H4B6O11
C4H10 + O2 = CO2 + H2O =>
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
NH2NH2 + H2O = NH2NH3{+} + OH{-} =>
NH2NH2 + H2O = NH2NH3{+} + OH{-}
MgCl + NaF = NaCl + MgF =>
MgCl + NaF = NaCl + MgF
TiO2 + KF + Al = KAlO2 + AlF3 + Ti =>
3 TiO2 + 3 KF + 4 Al = 3 KAlO2 + AlF3 + 3 Ti
C6H11C6H5 + Br2 = BrC6H10C6H5 + HBr =>
C6H11C6H5 + Br2 = BrC6H10C6H5 + HBr
Co(CH3CHOO)2 + Na2CO3 = CoCO3 + Na2(CH3CHOO)2 =>
Co(CH3CHOO)2 + Na2CO3 = CoCO3 + Na2(CH3CHOO)2
HA + OH = A + H2O =>
HA + OH = A + H2O
FeCl3 + K2CO3 + H2O = Fe(OH)3 + CO2 + KCl =>
2 FeCl3 + 3 K2CO3 + 3 H2O = 2 Fe(OH)3 + 3 CO2 + 6 KCl
(NH4)2CO3 + NaCl = NH4Cl + Na2CO3 =>
(NH4)2CO3 + 2 NaCl = 2 NH4Cl + Na2CO3
Cl2 + Ag = ClAg4 =>
Cl2 + 8 Ag = 2 ClAg4
NH4OH + HCl = NOH4 + ClH2 =>
NH4OH + HCl = NOH4 + ClH2
S + O2 + Pt + NaOH = PtOH + Na2SO4 =>
S + 2 O2 + 2 Pt + 2 NaOH = 2 PtOH + Na2SO4
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/27/23
Equations balanced on 12/27/22
-donnez-nous vos commentaires de votre expérience avec l'équilibreur d'équation chimique.